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\(=\dfrac{36\cdot22\cdot51}{11\cdot17\cdot72}=\dfrac{1}{2}\cdot3\cdot2=3\)
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
\(\frac{36x22x51}{11x17x72}\)=\(\frac{2x3}{2}\)=3
giảm ước 36 và 72, 22 và 11, 51 và 17
chữa :
a) \(\frac{6}{25}:\frac{21}{20}=\frac{6}{25}.\frac{20}{21}=\frac{6.20}{25.21}=\frac{3.2.4.5}{5.5.7.3}=\frac{8}{35}\)
623+x=1019
x=1019-623
x=396
413+(x+9)=1994
(x+9)=1994-413
x+9=1581
x=1581-9
x=1572
519+(73-x)=563
72-x =563 - 519
72- x=44
x=72-44
x=28
b. \(\dfrac{4.2.3.5.2.6.2.5.3}{4.3.4.5.6.4.5.6}=\dfrac{1}{4}\)
c. \(\dfrac{17.2.101.2005}{17.2.101.2.2005}=\dfrac{1}{2}\)
d. \(\dfrac{2.3.4.2.11.13.17}{3.11.4.4.17.13.2}=\dfrac{1}{2}\)
a)\(\dfrac{4\times6\times10\times12\times15}{4\times12\times5\times24\times30}=\dfrac{2}{2\times2\times2}=\dfrac{2}{8}=\dfrac{1}{4}\)
b)\(\dfrac{34\times101\times2005}{17\times202\times4010}=\dfrac{2}{2\times2}=\dfrac{2}{4}=\dfrac{1}{2}\)
c)\(\dfrac{6\times8\times11\times13\times17}{33\times16\times17\times26}=\dfrac{6}{3\times2\times2}=\dfrac{1}{2}\)
\(\frac{11}{3}:\frac{99}{21}-\frac{5}{18}\)
\(=\frac{11}{3}.\frac{21}{99}-\frac{5}{18}=\frac{7}{9}-\frac{5}{18}=\frac{14}{18}-\frac{5}{18}\)
\(=\frac{9}{18}=\frac{1}{2}\)
\(\frac{22\cdot13\cdot17}{55\cdot26\cdot51}\)
\(=\frac{22\cdot13\cdot17}{55\cdot13\cdot2\cdot3\cdot17}\)
\(=\frac{11\cdot2}{55\cdot2\cdot3}\)
\(=\frac{11}{55\cdot3}=\frac{11}{165}\)
\(\frac{22.13.17}{55.26.51}\) = \(\frac{2.11.13.17}{11.5.13.2.17.3}\) = \(\frac{1}{15}\)
. là dấu nhân nhé