a) [(286:11+7.2).3-199].2002+1

= [(26+14).3-199].2002+1

= [40.3-199].2002+1

= [120-199].2002+1

= -79.2002+1

= -158157

b) ko hiểu

c)1+6+11+16+...+2001+2006

số hạng của tổng là

(2006-1):2+1=1003,5

tổng

(2006+1).1003,5:2=1007012,25

d) (225-7²) . (225-10²) . (225-9²) . (225-15²)

=(15^2-7²) . (15²-10²) . (15²-9²) . (15²-15²)

=176.125.144.0

0 like nha

Dễ thế cũng hỏi ở trường tính hay lắm mà:

a) \(\dfrac{3}{7}.\dfrac{8}{11}+\dfrac{3}{7}.\dfrac{5}{11}-\dfrac{3}{7}.\dfrac{2}{11}\)

\(=\dfrac{3}{7}.\left(\dfrac{8}{11}+\dfrac{5}{11}-\dfrac{2}{11}\right)\)

\(=\dfrac{3}{7}.\left(\dfrac{8+5-2}{11}\right)=\dfrac{3}{7}.\dfrac{11}{11}=\dfrac{3}{7}\)

b) \(\dfrac{3}{13}.\dfrac{8}{25}+\dfrac{3}{13}.\dfrac{11}{25}+\dfrac{3}{13}.\dfrac{6}{25}-\dfrac{3}{13}\)

\(=\dfrac{3}{13}.\left(\dfrac{8}{25}+\dfrac{11}{25}+\dfrac{6}{25}-1\right)\)

\(=\dfrac{3}{13}.\left(\dfrac{8+11+6}{25}-1=\right)\dfrac{3}{13}.0=0\)

a,

\(\dfrac{3}{7}.\dfrac{8}{11}+\dfrac{3}{7}.\dfrac{5}{11}-\dfrac{3}{7}.\dfrac{2}{11}=\dfrac{3}{7}\left(\dfrac{8}{11}+\dfrac{5}{11}-\dfrac{2}{11}\right)=\dfrac{3}{7}.1=\dfrac{3}{7}\)

b,

\(\dfrac{3}{13}.\dfrac{8}{25}+\dfrac{3}{13}.\dfrac{11}{25}+\dfrac{3}{13}.\dfrac{6}{25}-\dfrac{3}{13}=\dfrac{3}{13}\left(\dfrac{8}{25}+\dfrac{11}{25}+\dfrac{6}{25}-1\right)=\dfrac{3}{13}.0=0\)

\(5^{36}=\left(5^3\right)^{12}=125^{12}>121^{12}=\left(11^2\right)^{12}=11^{24}\)

Câu A là hai phân số không bằng nhau nha bạn

b: \(-\dfrac{60}{185}=\dfrac{-60:5}{185:5}=\dfrac{-12}{37}\)

c: \(\dfrac{20022002}{20032003}=\dfrac{20022002:10001}{20032003:10001}=\dfrac{2002}{2003}\)

d: \(-\dfrac{3a}{6b}=\dfrac{-a}{2b}=\dfrac{5a}{-10b}\)

\(27^{11}=3^{33};81^8=3^{32}\)

\(27^{11}>81^8\)

\(5^{23}=5.5^{22}

a: \(A=21\cdot100-11\cdot100+90\cdot100+100\cdot125\cdot16\)

\(=100\left(21-11+90\right)+100\cdot2000\)

\(=100\left(10+90+2000\right)=2100\cdot100=210000\)

b: \(=\dfrac{5\cdot2^{30}\cdot3^{18}-2^{29}\cdot3^{20}}{5\cdot2^{28}\cdot3^{19}-7\cdot2^{29}\cdot3^{18}}\)

\(=\dfrac{2^{29}\cdot3^{18}\left(5\cdot2-3^2\right)}{2^{28}\cdot3^{18}\left(5\cdot3-7\cdot2\right)}=2\)