6 cap minh giai roi do

chinh xac roi 

Ta có :

\(\frac{a}{2}+\frac{b}{3}=\frac{a+b}{5}\)

\(\Leftrightarrow\frac{3a+2b}{6}=\frac{a+b}{5}\)

\(\Leftrightarrow15a+10b=6a+6b\)

\(\Leftrightarrow9a+3b=0\)

\(\Leftrightarrow a=-\frac{b}{3}\)

Vậy a , b thỏa mãn a = - b/3

vậy có tất cả là bao nhiêu cặp

\(\frac{x}{5}=\frac{y}{6}\Rightarrow\frac{x}{20}=\frac{y}{24};\frac{y}{8}=\frac{z}{7}\Rightarrow\frac{y}{24}=\frac{z}{21}\Rightarrow\frac{x}{20}=\frac{y}{24}=\frac{z}{21}=\frac{x+y-z}{20+24-21}=\frac{69}{23}=3\Rightarrow x=60;y=72;z=63\)

1,\(\Rightarrow\frac{x}{40}=\frac{y}{48}=\frac{z}{42}\)\(=\frac{69}{46}=\frac{3}{2}\)

=>x=60;y=72;z=63

2, t tự.

a./ \(\frac{x}{5}=\frac{y}{7}=\frac{z}{4}=\frac{x-y+z}{5-7+4}=\frac{-10}{2}=-5\)

\(\Rightarrow x=-25;y=-35;z=-20\)

b./ \(\frac{x}{5}=\frac{y}{-4}=\frac{z}{-7}=\frac{x+y-z}{5-4-\left(-7\right)}=\frac{-40}{6}=-5\)

\(\Rightarrow x=-25;y=20;z=35\)

Bài 1: 

\(B=\frac{\frac{1}{2}+\frac{3}{4}-\frac{5}{6}}{\frac{1}{4}+\frac{3}{8}-\frac{5}{12}}+\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{8}}{\frac{1}{4}+\frac{1}{5}-\frac{1}{8}}\)\(=\frac{\frac{1}{2}+\frac{3}{4}-\frac{5}{6}}{\frac{1}{2}\left(\frac{1}{2}+\frac{3}{4}-\frac{5}{6}\right)}+\frac{3\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{8}\right)}{\frac{1}{4}+\frac{1}{5}-\frac{1}{8}}\) 

\(=\frac{1}{\frac{1}{2}}+3\)  \(=2+3\) \(=5\)

                                                  Vậy B=5

Bài 2:

a) x³ - 36x = 0  

=>  x(x²-36)=0

=>  x(x²+6x-6x-36)=0 

=> x[x(x+6)-6(x+6) ]=0

=> x(x+6)(x-6)=0

\(\Rightarrow\orbr{\begin{cases}^{x=0}x+6=0\\x-6=0\end{cases}}\)

 \(\Rightarrow\orbr{\begin{cases}^{x=0}x=-6\\x=6\end{cases}}\)

                                  Vậy x=0; x=-6; x=6

b)  (x - y = 4 => x=4+y)

 x−3y−2 =32  

=>2(x-3) = 3(y-2)

=>2x-6= 3y-6

=>2x-3y=0

=>2(4+y)-3y=0

=>8+2y-3y=0

=>8-y=0

=>y=8 (thỏa mãn)

Do đó x=4+y=4+8=12 (thỏa mãn)

         Vậy x=12 và y =8

B= 1/2 + 3/4 - 5/6/1/2(1.2 + 3/4 - 5/6) + 3(1/4+ 1/5 - 1/8)/ 1/4  1/5 - 1/8 

B= 1/ 1/2 + 3

B= 2+3

B=5

B2:

a) x^3 - 36x = 0

x(x^2 - 36) = 0

=> x=0  hoặc x^2-36=0

=> x= 0 hoặc x^2=36

=> x=0 hoặc x= +- 6

-xx=-2x4

-xx=-8

xx=8

x²=8

x= căn bâc của 8

a; \(\dfrac{-x}{4}\) = \(\dfrac{-2}{x}\)

    -\(x.x\) = -2.4

    -\(x^2\) = -8

      \(x^2\) = 8

      \(\left[{}\begin{matrix}x=-\sqrt{8}\\x=\sqrt{8}\end{matrix}\right.\)

Vậy \(x\in\) {-\(\sqrt{8}\); \(\sqrt{8}\)}

Lời giải:

a,Ta có: \(\frac{33}{a}=\frac{45}{-120}=\frac{-y}{8}=\frac{z}{160}=\frac{3}{-8}\)

Do: \(\frac{33}{a}=\frac{3}{-8}\Rightarrow-8.33=3.a\Leftrightarrow-264=3.a\Leftrightarrow a=-88\)

\(\frac{-y}{8}=\frac{3}{-8}\Rightarrow8.y=3.8\Leftrightarrow y=3\)

\(\frac{z}{160}=\frac{3}{-8}\Rightarrow-8.z=3.160\Leftrightarrow-8.z=480\Leftrightarrow z=-60\)

Vậy: \(a=-88\) ; \(y=3\) ; \(z=-60\)

b, Ta có: \(\frac{x+1}{5}=\frac{y}{20}=\frac{6}{10}=\frac{3}{5}\)

Do: \(\frac{x+1}{5}=\frac{3}{5}\Rightarrow\left(x+1\right)5=3.5\Leftrightarrow x+1=3\Leftrightarrow x=2\)

\(\frac{y}{20}=\frac{3}{5}\Rightarrow y.5=3.20\Leftrightarrow y.5=60\Leftrightarrow y=12\)

Vậy: \(x=2\) ; \(y=12\)

Chúc bạn học tốt!Tick cho mình nhé!

\(\frac{6}{11}x=\frac{9}{2}y=\frac{18}{5}z\Rightarrow\frac{6x}{11.18}=\frac{9y}{2.18}=\frac{18z}{5.18}\)

\(\Rightarrow\frac{-x}{-33}=\frac{y}{4}=\frac{z}{5}=\frac{-x+y+z}{-33+4+5}=\frac{-120}{-24}=5\)

\(\Rightarrow x=165;y=20;z=25\)

\(\frac{x}{8}=-\frac{6}{12}\Leftrightarrow x=-4\)

\(\frac{-8}{y^2}=-\frac{6}{12}\Leftrightarrow y^2=16\Leftrightarrow y=4\)
\(\frac{z}{-18}=-\frac{6}{12}\Leftrightarrow z=9\)

Chúc bạn học tốt ^_^

\(\frac{x}{8}=\frac{-8}{y^2}=\frac{z}{-18}=-\frac{6}{12}\)

=>x=(-6).8:12=-4

y²=(-8).12:(-6)=16<=>y=+-4

z=(-6).(-18):12=9