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a; \(\dfrac{2}{3}\)\(x\) - \(\dfrac{3}{2}\)\(x\) = \(\dfrac{5}{12}\)
(\(\dfrac{2}{3}\) - \(\dfrac{3}{2}\))\(x\) = \(\dfrac{5}{12}\)
- \(\dfrac{5}{6}\)\(x\) = \(\dfrac{5}{12}\)
\(x\) = \(\dfrac{5}{12}\) : (- \(\dfrac{5}{6}\))
\(x=\) - \(\dfrac{1}{2}\)
Vậy \(x=-\dfrac{1}{2}\)
b; \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\) - \(\dfrac{2}{5}\)
\(\dfrac{3}{5}\).(3\(x\) - 3,7) = - \(\dfrac{57}{10}\)
3\(x\) - 3,7 = - \(\dfrac{57}{10}\) : \(\dfrac{3}{5}\)
3\(x\) - 3,7 = - \(\dfrac{19}{2}\)
3\(x\) = - \(\dfrac{19}{2}\) + 3,7
3\(x\) = - \(\dfrac{29}{5}\)
\(x\) = - \(\dfrac{29}{5}\) : 3
\(x\) = - \(\dfrac{29}{15}\)
Vậy \(x\) \(\in\) - \(\dfrac{29}{15}\)
Với $x=1$ ta có :
$-7.(x+3)^3 .|2x-1|+42$
$=-7.(-1+3)^3.|2.(-1)-1|+42$
$=-7.2^3.|-3|+42$
$=-7.8.3 + 42$
$=-126$
2x+12=3.(x-7)
2x+12=3.x-3.7
2x+12=3.x-21
2x+12=2x+x-21
12=x-21(hai bên đều trừ cho 2x)
x=12+21
x=33
Mình chắc chắn là đúng 100% đó nhá bạn ko tin thì bạn thử lại đi.
\(2x+12=3.\left(x-7\right)\)
\(2x+12=3x-21\)
\(2x+12-3x+21=0\)
\(33-x=0\Leftrightarrow x=33\)
Vay x=33
\(2x+12=3\left(x-7\right)\)
\(2x+12=3x-21\)
\(2x-3x=-21-12\)
\(-1x=-33\)
\(x=33\)
-12 .( x - 5 ) + 7 .( 3 - x ) = 5
-12x - ( -60 ) + 21 - 7x = 5
-12x + 60 + 21 - 7x = 5
( -12x - 7x ) + ( 60 + 21 ) = 5
-19x + 81 = 5
-19x = 5 - 81
-19x = -76
x = ( -76 ) : ( -19 )
x = 4
\(-5< x< 1\)
\(\Rightarrow\left\{-4;-3;-2;-1;0\right\}\)
Hok tốt
2x + 12 = 3(x - 7)
2x + 12 = 3x - 21
12 + 21 = 3x - 2x
33 = x
2x +12 =3(x -7)
2x + 12 =3x - 21
12+21=3x-2x
33=x