\(2^x+2^{x+1}+2^{x+2}=960-2^{x+3}\\ \Leftrightarrow2^x+2^{x+1}+2^{x+2}+2^{x+3}=960\\ \Leftrightarrow2^x+2^x.2+2^x.2^2+2^x.2^3=960\\ \Leftrightarrow2^x\left(1+2+2^2+2^3\right)=960\\ \Leftrightarrow2^x.15=960\\ \Leftrightarrow2^x=64\\ \Leftrightarrow2^x=2^6\\ \Leftrightarrow x=6\)

Vậy \(x=6\)

\(2^x+2^{x+1}+2^{x+2}=960-2^{x+3}\)

\(\Leftrightarrow2^x+2^{x+1}+2^{x+2}+2^{x+3}=960\)

\(\Leftrightarrow2^x\left(1+2+2^2+2^3\right)=960\)

\(\Leftrightarrow2^x.15=960\)

\(\Leftrightarrow2^x=64\)

\(\Leftrightarrow2^x=2^6\Leftrightarrow x=6\)

Vậy...

1: =>x+1/2=0 hoặc 2/3-2x=0

=>x=-1/2 hoặc x=1/3

2: =>7/6x=5/2:3,75=2/3

=>x=2/3:7/6=2/3*6/7=12/21=4/7

3: =>2x-3=0 hoặc 6-2x=0

=>x=3 hoặc x=3/2

4: =>-5x-1-1/2x+1/3=3/2x-5/6

=>-11/2x-3/2x=-5/6-1/3+1

=>-7x=-1/6

=>x=1/42

CHÚC EM HỌC TỐT NHÉ 

Tham Khảo:

2

2.(1+2+2+2)=480

2.15=480

2=480:15

2=32=2

x=5

Vậy x=5

ủa gòi hong bíc đường tra mạng hở :V

Giúp tớ với tớ cần ngay bây giờ

a. \(2\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)-\dfrac{3}{2}=\dfrac{1}{4}\\ \Leftrightarrow2\left(\dfrac{1}{2}x-\dfrac{1}{3}\right)=\dfrac{7}{4}\\ \Leftrightarrow\dfrac{1}{2}x-\dfrac{1}{3}=\dfrac{7}{8}\\ \Leftrightarrow\dfrac{1}{2}x=\dfrac{29}{24}\\ \Leftrightarrow x=\dfrac{29}{12}\)

b. \(\dfrac{3}{4}-2\left(2x-\dfrac{2}{3}\right)=2\\ \Leftrightarrow2\left(2x-\dfrac{2}{3}\right)=-\dfrac{5}{4}\\ \Leftrightarrow2x-\dfrac{2}{3}=-\dfrac{5}{8}\\ \Leftrightarrow2x=\dfrac{1}{24}\\ \Leftrightarrow x=\dfrac{1}{48}\)

c. \(\left(2x-3\right)\left(6-2x\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x-3=0\\6-2x=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\x=3\end{matrix}\right.\)

Vậy ..........

Có tất cả 2015 số hạng

Tổng bằng (2x+1+2x+2015).2015/2=0

4x+2016=0

4x=0-2016=-2016

x=(-2016):4=-504

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