0,2:x=1,03+3,97

a: A=-2xy+xy+xy^2=-xy+xy^2

Bậc là 3

b: \(B=xy^2z+2xy^2z-3xy^2z+xy^2z-xyz=-xyz+xy^2z\)

Bậc là 4

c: \(C=4x^2y^3-x^2y^3+x^4+6x^4-2x^2=3x^2y^3+7x^4-2x^2\)

Bậc là 5

d: \(D=\dfrac{3}{4}xy^2-\dfrac{1}{2}xy^2+xy=\dfrac{1}{4}xy^2+xy\)

bậc là 3

e: \(E=2x^2-4x^2+3z^4-z^4-3y^3+2y^3\)

=-2x^2+2z^4-y^3

Bậc là 4

f: \(=3xy^2z+xy^2z+2xy^2z-4xyz=6xy^2z-4xyz\)

Bậc là 4

\(a,\dfrac{2}{3}xy^2.\dfrac{2}{3}xy=\dfrac{4}{9}x^2y^3\)

\(b,-\dfrac{1}{2}x^2y.2xy^2=-x^3y^3\)

\(c,8xy^3.2x^3y^2=16x^4y^5\)

\(d,-\dfrac{1}{4}x^2y^3.2x^3y^2=-\dfrac{1}{2}x^5y^5\)

\(e,4x^2y^4.\dfrac{1}{2}x^2y^3=2x^4y^7\)

\(f,-8xy.\dfrac{1}{4}x^2y=-2x^3y^2\)

\(Ayumu\)

a) 5xy² . (-3y)²

= 5xy² . 9y²

= (5.9).x.(y².y²)

= 45xy⁴

Hệ số: 45

Bậc: 5

b) x²yz . (-2xy)³

= x²yz . (-8x³y³)

= -8.(x².x³).(y.y³).z

= -8x⁵y⁴z

Hệ số: -8

Bậc: 10

c) (-2x²y)².8x³yz³

= 4x⁴y².8x³yz³

= (4.8).(x⁴.x³).(y².y).z³

= 32x⁷y³z³

Hệ số: 32

Bậc: 13

d) (-2xy³)².(-2xyz)³

= 4x²y⁶.(-8x³y³z³)

= [4.(-8)].(x².x³).(y⁶.y³).z³

= -32x⁵y⁹z³

Hệ số: -32

Bậc: 17

e) (-5xy³z).(-4x²)²

= (-5xy³z).(16x⁴)

= (-5.16).(x.x⁴).y³.z

= -80x⁵y³z

Hệ số: -80

Bậc: 9

f) (2x²y³)².(-2xy)

= (4x⁴y⁶).(-2xy)

= [4.(-2)].(x⁴.x).(y⁶.y)

= -8x⁵y⁷

Hệ số: -8

Bậc: 12

a: =5xy^2*9y^2=45xy^4

b: =x^2yz*(-8)x^3y^3=-8x^5y^4z

c: =4x^4y^2*8x^3yz^3=32x^7y^3z^3

d: =4x^2y^6*(-8)x^3y^3z^3=-32x^5y^9z^3

e: =-5xy^3z*16x^4=-80x^5y^3z

f: =4x^4y^6*(-2xy)=-8x^5y^7

Lời giải:

$2x^3y+2xy^3+4x^2y^2-8xy$

$=2xy(x^2+y^2+2xy-4)$

$=2xy[(x^2+2xy+y^2)-4]$

$=2xy[(x+y)^2-2^2]=2xy(x+y-2)(x+y+2)$

P.s: lần sau bạn lưu ý ghi đầy đủ yêu cầu đề.

1/x^3 - 2x^2 - 9x + 18

= x\(^2\)( x - 2 ) - 9 ( x - 2 ) = ( x\(^2\) - 9 ) ( x - 2 )= ( x - 3 ) ( x +3 ) ( x - 2 )

2/3x^2 -5x - 3y^2 + 5y

= 3( x\(^2\) - y\(^2\) ) - 5 ( x - y ) = 3 ( x - y ) ( x + y ) - 5 ( x - y ) = ( x - y ) [ 3( x+ y ) - 5 ]

= ( x - y ) ( 3x + 3y - 5 )

3/49 - x^2 + 2xy - y^2

= 49 - ( x\(^2\) - 2xy + y\(^2\) ) = 49 - ( x - y )\(^2\) = ( 7 - x + y ) ( 7 + x - y )

5/ x^2 - 4x^2y^2 + 2xy

= x ( x - 4xy\(^2\) + 2y )

6/ 3x - 3y - x^2 + 2xy - y^2

= ( 3x - 3y ) - ( x\(^2\) - 2xy + y\(^2\) ) = 3 ( x - y ) - ( x - y )\(^2\) = ( x - y ) ( 3 - x + y )

a: \(=x^2-4-x^2+x+8=x+4\)

a) (x-2)(x+2)-x(x-1)+8
= x²-4-x²+x+8
= (x²-x²)+(-4+8)+x
= 4+x
b) bn viết lại đề đi:v
đọc khó quá.