\(\dfrac{5}{4x}-\dfrac{3}{2}=\dfrac{3}{2}+\dfrac{x}{2}\\ \Leftrightarrow5-6x=6x+2x^2\\ \Leftrightarrow2x^2+12x-5=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-6+\sqrt{46}}{2}\\x=\dfrac{-6-\sqrt{46}}{2}\end{matrix}\right.\)

          (25-2X)^3:5-3^2=4^2

(25-2X)^0,6-9=16

(25-2X)^0,6=16+9=25

..............................

=>x=-94,37349667

2x-1-2x=2019

(=)-1=2019(vô lý)

vậy không có x thỏa mãn 2x-1-2x=2019

#Học-tốt(sai đề gửi lại nha)

đứa tích sai giải thik jup t -1=2019????

#Học-tốt(đứa nào tích sai nên xem lại toán cấp 1)

(1+3+5+7+...+1995)+2x=996006

[(1995+1).998 : 2] + 2x = 996006

996004+2x=996006

=> 2x = 2

=> x=1

(1+3+5+7+...+1995)+2x=996006

[(1995+1).998 : 2] + 2x = 996006

996004+2x=996006

=> 2x = 2

=> x=1

Ta có : 5 + ( 2x - 1 ) = -6 - ( 5 + x ) 

=> 5 + 2x - 1 = -6 - 5 - x 

=> 4 + 2x = -x - 11 

=> 2x + x = -11 - 4

=> 3x = -15

=> x = ( -15 ) : 3 = -5

\(2x+3=9×\frac{2}{3}\)

\(\Leftrightarrow2x+3=6\)

\(\Leftrightarrow2x=3\Leftrightarrow x=\frac{3}{2}\)

a) \(13\cdot\left(7-x\right)=26\)

\(\Rightarrow7-x=\dfrac{26}{13}\)

\(\Rightarrow7-x=2\)

\(\Rightarrow x=7-2\)

\(\Rightarrow x=5\)

b) \(\left(4x-18\right):3=2\)

\(\Rightarrow4x-18=2\cdot3\)

\(\Rightarrow4x-18=6\)

\(\Rightarrow4x=6+18\)

\(\Rightarrow4x=24\)

\(\Rightarrow x=24:4\)

\(\Rightarrow x=6\)

c) \(2\cdot x+98\cdot2022=98\cdot2023\)

\(\Rightarrow2\cdot x=98\cdot2023-98\cdot2022\)

\(\Rightarrow2\cdot x=98\cdot\left(2023-2022\right)\)

\(\Rightarrow2\cdot x=98\cdot1\)

\(\Rightarrow x=\dfrac{98}{2}\)

\(\Rightarrow x=49\)

d) \(\left(x+1\right)+\left(x+3\right)+\left(x+5\right)+...+\left(x+101\right)=?\)

Thiếu đề 

a) \(13.\left(7-x\right)=26\)

\(7-x=26:13\)

\(7-x=2\)

\(x=7-2\)

\(x=5\)

b) \(\left(4x-18\right):3=2\)

\(4x-18=6\)

\(4x=6+18\)

\(4x=24\)

\(x=24:4\)

\(x=6\)