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\(3-\left(\frac{5}{\frac{3}{8}}+x-\frac{7}{\frac{5}{24}}\right):\frac{16}{\frac{2}{3}}=2\)
\(\Rightarrow3-\left(\frac{40}{3}+x-\frac{168}{5}\right):24=2\)
\(\Rightarrow\left(-\frac{304}{15}+x\right):24=1\)
\(\Rightarrow\frac{-304}{15}+x=24\)
\(\Rightarrow x=\frac{664}{15}\)
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(\Rightarrow1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)
\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{53}{3}\)
\(\Rightarrow\frac{43}{8}+x=\frac{53}{3}+\frac{173}{24}\)
\(\Rightarrow\frac{43}{8}+x=\frac{199}{8}\)
\(\Rightarrow x=\frac{199}{8}-\frac{43}{8}\)
\(\Rightarrow x=\frac{156}{8}=\frac{39}{2}\)
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(< =>1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(< =>1\left(\frac{43}{8}+x-\frac{173}{24}\right)=0\)
\(< =>\frac{43}{8}+x-\frac{173}{24}=0\)
\(< =>\frac{43}{8}+x=\frac{173}{24}\)
\(< =>x=\frac{173}{24}-\frac{43}{8}\)
\(< =>x=\frac{11}{6}\)
câu 1 = 0
câu 2 : X=\(\frac{16}{105}\)
X =\(\frac{180}{77}\)
X = 63
(18\(\dfrac{1}{2}+5\dfrac{3}{8}-7\dfrac{5}{24}\)) - 16\(\dfrac{2}{3}\)
=( \(\dfrac{37}{2}\) + \(\dfrac{43}{8}\) - \(\dfrac{171}{24}\) ) - \(\dfrac{50}{3}\)
= \(\dfrac{50}{3}\) - \(\dfrac{50}{3}\)
=0
a) chắc bạn cũng biết
b) \(\frac{2005.2007-1}{2004+2005.2006}=\frac{2005.\left(2006+1\right)-1}{2004+2005.2006}=\frac{2005.2006+2005.1-1}{2004+2005.2006}=\frac{2005.2006+2004}{2004+2005.2006}=1\)
\(3-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=2\)
\(3-\left(\frac{43}{8}+x-\frac{173}{24}\right)=2×\frac{50}{3}\)
\(3-\left(\frac{43}{8}+x-\frac{173}{24}\right)=\frac{100}{3}\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right)=3-\frac{100}{3}\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right)=-\frac{91}{3}\)
\(\frac{43}{8}+x=-\frac{91}{3}+\frac{173}{24}\)
\(\frac{43}{8}+x=-\frac{185}{8}\)
\(x=-\frac{185}{8}-\frac{43}{8}\)
\(x=-\frac{57}{2}\)
vậy \(x=-\frac{57}{2}\)
nhầm
\(3-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=2\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=3-2\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right)=1×\frac{50}{3}\)
\(\left(\frac{43}{8}+x-\frac{173}{24}\right)=\frac{50}{3}\)
\(\frac{43}{8}+x=\frac{50}{3}+\frac{173}{24}\)
\(\frac{43}{8}+x=\frac{191}{8}\)
\(x=\frac{191}{8}-\frac{43}{8}\)
\(x=\frac{37}{2}\)
vậy \(x=\frac{37}{2}\)
a.1/4 +3/8 +5/16=15/16
b, 3/5 - 1/3 -1/6=1/10
c, 4/7 *5/8 *7/12=5/24
d. 25/28 : 15/24 * 6/7=60/49
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