\(42-\left(2x+32\right)-12:\left(-2\right)=6\)

\(42-2x-32+12:2=6\)

\(\left(42-32+6-6\right)-2x=0\)

\(10-2x=0\)

\(x=5\)

\(\left(x-15\right):\left(-5\right)-\left(-22\right)=24\)

\(\left(x-15\right):\left(-5\right)+22=24\)

\(\left(x-15\right):\left(-5\right)=2\)

\(x-15=2\cdot\left(-5\right)\)

\(x-5=-10\)

\(x=-5\)

42−(2x+32)−12:(−2)=6

42−2x−32+12:2=6

10−2x=0

(x−15):(−5)−(−22)=24

(x−15):(−5)+22=24

(x−15):(−5)=2

x−15=2·(−5)

x−5=−10

x=−5

ta có 16 + 7n chia hết cho n+1

7n+7 +9 chia hết cho n+1

7(n+1) +9 chia hết cho n+1

vì 7(n+1) chia hết cho n+1 nên 9 chia hết cho n+1 

=) n+1 là Ư(9)  và Ư(9)={-1;1-3;3-9;9}

từ đó =) ta có bảng sau

16+7n chia hết n+1,7(n+1) chia hết cho n+1

=>16+7n-7(n+1) chia hết cho n+1<=>9 chia hết cho n+1

=>n=8;n=2;n=0

abcabc=abc.1001

2 số cần tìm chia hết cho 16

=>abcabc chia hết cho 16²

=>abcabc chia hết cho 256

=>abc chia hết cho 256

=>abc=256;512

từ đó rồi tìm

\(d,\dfrac{5}{7}+\dfrac{9}{23}+-\dfrac{12}{7}+\dfrac{14}{23}\)

\(=\left(\dfrac{5}{7}+\dfrac{-12}{7}\right)+\left(\dfrac{9}{23}+\dfrac{14}{23}\right)\)

\(=-\dfrac{7}{7}+\dfrac{23}{23}\)

\(=\left(-1\right)+1=0\)

\(e,\dfrac{3}{17}+-\dfrac{5}{13}+-\dfrac{18}{35}+\dfrac{14}{17}+\dfrac{17}{-35}+-\dfrac{8}{13}\)

\(=\left(\dfrac{3}{17}+\dfrac{14}{17}\right)+\left(\dfrac{-5}{13}+\dfrac{-8}{13}\right)+\left(\dfrac{-18}{35}+\dfrac{-17}{35}\right)\)

\(=\dfrac{17}{17}+\dfrac{-13}{13}+-\dfrac{35}{35}\)

\(=1+\left(-1\right)+\left(-1\right)=0+\left(-1\right)=-1\)

\(f,\dfrac{-3}{8}. \dfrac{1}{6}+\dfrac{3}{-8}.\dfrac{5}{6}+\dfrac{-10}{16}\)

\(=\dfrac{-3}{8}.\dfrac{1}{6}+\dfrac{-3}{8}.\dfrac{5}{6}+\dfrac{-10}{16}\)

\(=\dfrac{-3}{8}.\left(\dfrac{1}{6}+\dfrac{5}{6}\right)+-\dfrac{10}{16}\)

=\(\dfrac{-3}{8}.1+\dfrac{-10}{16}\)

\(=\dfrac{-3}{8}+\dfrac{-10}{16}\)

\(=\dfrac{-6}{16}+\dfrac{-10}{16}=\dfrac{-16}{16}=-1\)

\(g,\dfrac{-4}{11}.\dfrac{5}{15}.\dfrac{11}{-4}=\dfrac{-4}{11}.\dfrac{5}{15}.\dfrac{-11}{4}\)

\(=\left(\dfrac{-4}{11}.\dfrac{-11}{4}\right).\dfrac{5}{15}\)

\(=1.\dfrac{5}{15}=1.\dfrac{1}{3}=\dfrac{1}{3}\)

\(h,\dfrac{7}{36}-\dfrac{8}{-9}+\dfrac{-2}{3}=\dfrac{7}{36}-\dfrac{-8}{9}+\dfrac{-2}{3}\)

\(=\dfrac{7}{36}-\dfrac{-32}{36}+\dfrac{-24}{36}=\dfrac{7-\left(-32\right)+\left(-24\right)}{36}\)

\(=\dfrac{15}{56}=\dfrac{5}{12}\)

Tick mình nha ^^

d.\(\dfrac{5}{7}\)+\(\dfrac{9}{23}\)+\(\dfrac{12}{7}\)+\(\dfrac{14}{23}\)=(\(\dfrac{5}{7}\)+\(\dfrac{12}{7}\))+(\(\dfrac{9}{23}\)+\(\dfrac{14}{23}\))

                            =\(\dfrac{17}{7}\)+ 1 = \(\dfrac{24}{7}\)

e.\(\dfrac{3}{17}\)+\(\dfrac{-5}{13}\)+\(\dfrac{-18}{35}\)+\(\dfrac{14}{17}\)+\(\dfrac{17}{-35}\)+\(\dfrac{-8}{13}\)

=(\(\dfrac{3}{17}\)+\(\dfrac{14}{17}\))+(\(\dfrac{-5}{13}\)+\(\dfrac{-8}{13}\))+(\(\dfrac{-18}{35}\)+\(\dfrac{17}{-35}\))

= 1+ (-1) + (-1) = -1

f. \(\dfrac{-3}{8}\).\(\dfrac{1}{6}\)+\(\dfrac{3}{-8}\).\(\dfrac{5}{6}\)+\(\dfrac{-10}{16}\)=\(\dfrac{-3}{8}\)(\(\dfrac{1}{6}\)+\(\dfrac{5}{6}\)) + \(\dfrac{-5}{8}\)

                                   =\(\dfrac{-3}{8}\)+\(\dfrac{-5}{8}\)= -1

g. \(\dfrac{-4}{11}\).\(\dfrac{5}{15}\).\(\dfrac{11}{-4}\)=\(\dfrac{5}{15}\)

h.\(\dfrac{7}{36}\)-\(\dfrac{8}{-9}\)+\(\dfrac{-2}{3}\)= \(\dfrac{7}{36}\)-\(\dfrac{-32}{36}\)+\(\dfrac{-24}{36}\)

                       =\(\dfrac{-49}{36}\)

27.(13-16)-16.(13-27)

=27.13-27.16-16.13+16.27

=(27.13-16.13)-(27.16-16.27)

=13(27-16)-0

=13.11

=143

mk làm chuẩn rồi đó bạn

tính  bằng 143 chọn mình nha bạn mình cho nick  manh ưng nich gì mình gửi qua tin nhắn cho

45=54

23=32: đó là do thay đổi thứ tự các số thôi

tick nha

54

=( 22 . 34) . (15 .11)

= 748 . 165

= 123420

=> M = 123420

Nhớ giữ lời hứa nha .

Thank you .............!!

r đó :D

a. x : 13/16 = 5/-8

    x : 13/16 = -5/8

    x             = -5/8 . 13/16

    x             = -65/128

b.

x . \(\dfrac{-14}{28}\) = \(\dfrac{6}{-9}\) - \(\dfrac{2}{15}\)

x . \(\dfrac{-14}{28}\) = \(\dfrac{-9}{6}\) - \(\dfrac{2}{15}\)

x . \(\dfrac{-14}{28}\) = \(\dfrac{-49}{30}\)

x            = \(\dfrac{-49}{30}\) : \(\dfrac{-14}{28}\)

x            = \(\dfrac{-49}{30}\) . \(\dfrac{-28}{14}\)

x            = \(\dfrac{-49}{15}\)

a) 18.(x-16)=18

x-16= 18:18

x-16=1

x=16+1

x=17

b) (x.34).15= 0

x-34= 0:15

x-34= 0

x=34+0

x=34 

nhớ cho mk nha

a) 18.(x-16)=18

    x-16= 1

   x= 17

Vậy x=17

b) (x-34).15=0

x-34=0

x=34 

Vậy x=34

nhớ k cho mk nhá, mk kb vs bn r đó, vs lại mk cx đang bị   âm điểm..