\(\frac{3}{2}+\frac{5}{4}+\frac{9}{8}+\frac{17}{16}+\frac{31}{32}+\frac{65}{64}-7\)

\(=\left(1+\frac{1}{2}\right)+\left(1+\frac{1}{4}\right)+\left(1+\frac{1}{8}\right)+.....+\left(1+\frac{1}{64}\right)-7\)

\(=6+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\right)-7\)

\(=.....................\)

\(\frac{3}{2}+\frac{5}{4}+\frac{9}{8}+\frac{17}{16}+\frac{33}{32}+\frac{65}{64}-7\) \(7\)

\(=2\frac{3}{4}+\frac{9}{8}+\frac{17}{16}+\frac{33}{32}+\frac{65}{64}-7\)

\(=3\frac{7}{8}+\frac{17}{16}+\frac{33}{32}+\frac{65}{64}-7\)

\(=4\frac{15}{16}+\frac{33}{32}+\frac{65}{64}-7\)

\(=5\frac{31}{32}+\frac{65}{64}-7\)

\(=6\frac{63}{64}-7\)

\(=-\frac{1}{64}\)

Mình có cách như vậy thôi nhé, vì mình mới học lớp 5

3/2 + 5/4 + 9/8 + 17/6 + 33/32 + 65/2 - 7 

=(3/2+5/4+33/32+65/2) + 9/8+17/6 -7

= 1161/32 + 95/24 - 7

= 3191/26

3/2 + 5/4 + 9/8 + 17/6 + 33/32 + 65/2 - 7 = \(\frac{3191}{96}\)

\(A=\frac{-11}{13}\)

\(B=\frac{-1}{64}\)
 

A=\(\frac{1}{3}-\frac{3}{5}+\frac{5}{7}-\frac{7}{9}+\frac{9}{11}-\frac{11}{13}-\frac{9}{11}+\frac{7}{9}-\frac{5}{7}+\frac{3}{5}-\frac{1}{3}\)

A=[ \(\frac{1}{3}-\frac{1}{3}\)] + [ \(-\frac{3}{5}+\frac{3}{5}\)] + [  \(-\frac{5}{7}+\frac{5}{7}\)] + [  \(-\frac{7}{9}+\frac{7}{9}\)] + [  \(-\frac{9}{11}+\frac{9}{11}\)] \(-\frac{11}{13}\)

Các bạn tự làm tiếp nhé!Sorry

a: \(=3\cdot\left(\dfrac{1}{4}-\dfrac{6}{7}+\dfrac{8}{21}\right)\)

\(=3\cdot\left(\dfrac{21}{84}-\dfrac{72}{84}+\dfrac{32}{84}\right)\)

\(=\dfrac{-19}{28}\)

b: \(=\dfrac{-2}{3}\left(\dfrac{1}{9}-\dfrac{1}{6}-\dfrac{1}{11}\right)\)

\(=\dfrac{-2}{3}\cdot\dfrac{-29}{198}=\dfrac{29}{99\cdot3}=\dfrac{29}{297}\)

c: \(=\dfrac{-3}{7}+\dfrac{4}{25}+\dfrac{5}{16}+\dfrac{3}{16}\)

\(=\dfrac{-75+28}{175}+\dfrac{1}{2}\)

\(=\dfrac{-47}{175}+\dfrac{1}{2}=\dfrac{-94+175}{350}=\dfrac{81}{350}\)

d: \(=\dfrac{-4}{9}\cdot\left(\dfrac{1}{26}-\dfrac{1}{2}-\dfrac{1}{8}\right)\)

\(=\dfrac{-4}{9}\cdot\dfrac{-61}{104}=\dfrac{61}{26\cdot9}=\dfrac{61}{234}\)

wow! mù mắt. Ido tính toán có khác!

C2:(32+1)x32:2=528

bạn tính thử xem đúng đấy.

8: =>2x=210

hay x=105

\(P=...\)

\(=\frac{1}{99}-\frac{1}{99}+\frac{1}{98}-\frac{1}{98}+\frac{1}{97}-...-\frac{1}{2}+1\)

\(=\frac{1}{99}-1=\frac{-98}{99}\)

\(M=...\)

\(=\frac{2}{2}+\frac{1}{2}+\frac{4}{4}+\frac{1}{4}+...+\frac{64}{64}+\frac{1}{64}-7\)

\(=1+1+1+1+1+1+\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}+\frac{1}{2^6}-7\)

\(=\frac{1+2+2^2+2^3+2^4+2^5}{2^6}-1\)

\(=\frac{2^6-1}{2^6}-1=1-\frac{1}{2^6}-1=-\frac{1}{2^6}\)

3/2+5/4+9/8/+17/16+33/32-6+x-1/x+1=31/32-2/2015

=(1+1/2)+(1+1/4)+(1+1/8)+(1+1/16)+(1+1/32-6+x-1/x+1=31/32-2/2015

=(1/2+1/4+1/8+1/16+1/32)+(1+1+1+1+1)-6+x-1/x+1=31/32-2/2015

=31/32+5-6+x-1/x+1=31/32-2/2015

=5-6+x-1/x+1=31/32-2/2015-31/32

=-1+x-1/x+1=-2/2015

=x-1/x+1=-2/2015- -1

=x-1/x+1=2013/2015

=>x=2014