Câu này em viết đề lại cho chính xác giùm

Sửa đề: \(\dfrac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^{10}}\)\(=\dfrac{\left(3\cdot2^{18}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^{10}}=\dfrac{3\cdot2^{36}}{2^{35}\left(11-2^5\right)}=\dfrac{2\cdot3}{11-32}=\dfrac{-6}{21}=\dfrac{-2}{7}\)

RÚT GỌN VỀ PHÂN SỐ TỐI GIẢN

câu a) \(\dfrac{-147}{252}=\dfrac{-7}{12}\)

câu b) \(\dfrac{765}{900}=\dfrac{17}{20}\)

câu c) \(\dfrac{11\cdot3-11\cdot8}{17-6}=\dfrac{-5}{1}\)

câu d) \(\dfrac{3^5\times2^4}{8\times3^6}=\dfrac{2}{3}\)

câu e) \(\dfrac{84\cdot45}{49\cdot54}=\dfrac{10}{7}\)

\(A=4^3-6^3:6^2+11\cdot3^2\\ =64-6+11\cdot9\\ =58+99\\ =157\\ B=5\cdot35-5^2\cdot2\\ =5\cdot\left(35-10\right)\\ =5\cdot25\\ =125\\ C=\left(7-3^3:3^2\right):2^2+99\\ =\left(7-3\right):4+99\\ =4:4+99\\ =1+99=100\\ D=2^7:2^2+5^4:5^3\cdot2^4-3\cdot2^5\\ =2^5+5\cdot2^4-6\cdot2^4\\ =2^4\cdot\left(2+5-6\right)\\ =2^4\\ =16\)

đợi tý

giúp em với 

\(=\dfrac{11\cdot\left(-5\right)}{11}=-5\)

Câu 1 dễ mà :

1.2.3...9 - 1.2.3...8 - 1.2.3...7.8²

= 1.2.3...8.9 - 1.2.3...8.1 - 1.2.3...7.8.8

= 1.2.3...8.( 9 - 1 - 8 )

= 1.2.3...8.0

= 0

còn câu 2 và 3 thì sao

*Bài làm:

\(\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}\)

= \(\frac{3.2^2.2^{16}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)

= \(\frac{3.2^{18}}{11.2^{13}.2^{22}-2^{36}}\)

= \(\frac{3.2^{18}}{11.2^{35}-2^{36}}\)

= \(\frac{3.2^{18}}{2^{18}.\left(11.2^{17}-2^{18}\right)}\)

= \(\frac{3}{\left(11.2^{17}-2^{18}\right)}\)

= \(\frac{3}{2^{17}.\left(11-2\right)}\)

= \(\frac{3}{2^{17}.9}\)

= \(\frac{1}{2^{17}.3}\)

*Vậy \(\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}\) = \(\frac{1}{2^{17}.3}\) .