Hì hì xin lỗi trả lời muộn thông cảm

\(a.x-143=57\)

\(x=200\)

\(b.\left(8x-12\right):4=3^3\)

\(8x-12=27.4\)

\(8x-12=108\)

\(8x=120\)

\(x=15\)

\(d.10+2x=4^2\)

\(2x=16-10\)

\(2x=6\)

\(x=3\)

mk cx có bài giống cậu đấy

tớ ko giai dai

a,\(2^4\cdot3^5:6^4\)

\(=\frac{2^4\cdot3^6}{\left(2\cdot3\right)^4}\)

\(=\frac{2^4\cdot3^6}{2^4\cdot3^4}\)

\(=3^2\)

Bài 2

\(a,5^3\cdot8=5^3\cdot2^3=10^3=1000\)

\(b,2^5-2019^0=32-1=31\)

\(c,3^3+2^5-1^{10}=27+32-1=58\).

\(d,9^2\cdot33-81\cdot23+5^2=81\cdot33-81\cdot23+25\)

\(=81\cdot\left(33-23\right)+25\)

\(=810+25=835\)

\(g,\left[2^2+6^2\right]:5+11^2\)

\(=\left[4+36\right]:5+121\)

\(=40:5+121=8+121\)

\(=129\)

\(d,\frac{14\cdot3^{10}-5\cdot3^{10}}{3^{12}}\)

\(=\frac{3^{10}\cdot\left(14-5\right)}{3^{12}}\)

\(=\frac{3^{10}\cdot9}{3^{12}}\)

\(=\frac{3^{10}\cdot3^2}{3^{12}}=\frac{3^{12}}{3^{12}}\)

\(=1\)

ma doi

Nguyễn Khánh Phương

Bài 1 :

a) 149 - ( 35 : x + 3 ) x 17 = 13

              ( 35 : x + 3 ) x 17 = 149 - 13 

               ( 35 : x + 3 ) x 17 = 136

                ( 35 : x + 3 )       = 136 : 17

                  ( 35 : x + 3 )     = 8

                    35 - x             = 8 - 3 

                    35 - x             = 5

                            x = 35 - 5

                            x = 30

b, 121 : 11 − ( 4x + 5 )  : 3 = 4
11 − 4x + 5 : 3 = 4
4x + 5 : 3 = 11 − 4
4x + 5 : 3 = 7
4x + 5 = 7 x 3
4x + 5 = 21
4x = 21 − 5
4x = 16

x = 16 : 4

  x = 4

\(A=5+3^2+3^3+...+3^{2018}\)

\(3A=15+3^3+3^4+...+3^{2019}\)

\(3A-A=\left(15+3^3+3^4+...+3^{2019}\right)-\left(5+3^2+3^3+...+3^{2018}\right)\)

\(2A=1+3^{2019}\)

\(2A-1=3^{2019}\)

Suy ra \(n=2019\).