`x+4/5=4/5+(3/7+3/5)`

`=> x+4/5=4/5+36/35`

`=> x+4/5= 64/35`

`=>x= 64/35 -4/5`

`=>x=  64/35 - 28/35`

`=>x= 36/35`

`----`

`5/7 + x/35 =4/5`

`=>x/35 =4/5-5/7`

`=>x/35 =28/35 - 25/35`

`=> x/35= 3/35`

`=>x=3`

\(x+\dfrac{4}{5}=\dfrac{45}{5}-\left(\dfrac{3}{7}+\dfrac{3}{5}\right)\\ \Rightarrow x+\dfrac{4}{5}=9-\dfrac{36}{35}\\ \Rightarrow x+\dfrac{4}{5}=\dfrac{279}{35}\\ \Rightarrow x=\dfrac{279}{35}-\dfrac{4}{5}\\ \Rightarrow x=\dfrac{251}{35}\\ \dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\\ \Rightarrow\dfrac{x}{35}=\dfrac{4}{5}-\dfrac{5}{7}\\ \Rightarrow\dfrac{x}{35}=\dfrac{3}{35}\\ \Rightarrow x=3\)

`x + 4/5= 45/5 -( 3/7 + 3/5)`

`=> x+ 4/5=9 - 36/35`

`=> x+ 4/5=279/35`

`=> x= 279/35 -4/5`

`=>x= 251/35`

__

`5/7 + x/35 = 4/5`

`=>  x/35 = 4/5-5/7`

`=>  x/35 =28/35 - 25/35`

`=> x/35= 3/35`

`=>x=3`

`@ `\(MinYewCou\)

ok

\(a,x+\dfrac{4}{5}=\dfrac{45}{5}-\left(\dfrac{3}{7}+\dfrac{3}{5}\right)\)

\(x+\dfrac{4}{5}=9-\dfrac{3}{7}-\dfrac{3}{5}\)

\(x+\dfrac{4}{9}=\dfrac{279}{35}\)

\(x=\dfrac{279}{35}-\dfrac{4}{9}\)

\(x=\dfrac{251}{35}\)

\(b,\dfrac{5}{7}+\dfrac{x}{35}=\dfrac{4}{5}\)

\(\dfrac{5}{7}+\dfrac{x}{35}-\dfrac{4}{5}=0\)

\(\dfrac{25}{35}+\dfrac{x}{35}-\dfrac{28}{35}=0\)

\(25+x-28=0\)

\(x=3\)

a: =>x=3/7+3/5=15/35+21/35=36/35

b: =>x/35=4/5-5/7=28/35-25/35=3/35

=>x=3

c: =>x<3/4+8/4=11/4

=>\(x\in\left\{0;1;2;3\right\}\)

d: =>5/3<x<5/6+24/6=29/6

=>\(x\in\left\{2;3;4\right\}\)

e: =>x<10/12-9/12=1/12

=>x=0

f: =>2/3<x<12/6-5/6=7/6

=>x=1

2/3 = 2 x 4/ 3 x 4 =8/12

8/14 = 8 : 2/ 14 : 2 =4/7

5/9 = 5 x3/ 9 x 3 =15/37

35/ 40 = 35 : 5/ 40 : 5=7/8

a: =>x+7/4=6:2/3=9

=>x=29/4

b: =>x:5/3=7/5

=>x=7/5*5/3=7/3

c:=>x+1/6=5/3

=>x=10/6-1/6=3/2

d: =>x+4/5=4/5+3/7+3/5

=>x=3/7+3/5=36/35

e: =>x/35=4/5-5/7=3/35

=>x=3

f: =>13/28+x=1/2

=>x=1/28

g: =>1/3-x=1/9

=>x=2/9

Gửi kết bn với mh nhé!

ban ko tra loi ho minh cau nay a 

neu the minh ket ban kieu gi

a, ta thấy cả hai vế đều có 4/5 mà lại bằng nhau nên x bằng số hạng còn lại ở vế phải 

x=3/7+3/5

x=36/35

b,x là số hạng chưa biết nên

x=4/5-5/7

x=3/35

cảm ơn Kiều Ngọc Lan tớ đứng đầu olm lớp 4 đấy

\(x+\frac{4}{5}=\frac{45}{5}-\left(\frac{3}{7}+\frac{3}{5}\right)\)

\(x+\frac{4}{5}=9-\frac{36}{35}\)

\(x+\frac{4}{5}=\frac{279}{35}\)

\(\Rightarrow x=\frac{251}{35}\)

\(x+\frac{4}{5}=\frac{45}{5}-\left(\frac{3}{7}+\frac{3}{5}\right)\)

\(\Leftrightarrow x+\frac{4}{5}=9-\left(\frac{3}{7}+\frac{3}{5}\right)\)

\(\Leftrightarrow x+\frac{4}{5}=9-\frac{3}{7}-\frac{3}{5}\)

\(\Leftrightarrow x+\frac{4}{5}=\frac{315}{35}-\frac{15}{35}-\frac{21}{35}\)

\(\Leftrightarrow x+\frac{4}{5}=\frac{279}{35}\)

\(\Leftrightarrow x=\frac{279}{35}-\frac{4}{5}\)

\(\Leftrightarrow x=\frac{251}{35}\)