\(46-44+44-42+42-40+...+4-2\)

\(=46-2\)

\(=44\)

Ta có \(46-44+44-42+42-40+40+...+4-2\)

\(=46+\left(-44+44\right)+\left(-42+42\right)+...+\left(-4+4\right)-2\)

\(=46-2\)

\(=44\)

a: Số số hạng là:

(40-2):2+1=20(số)

Tổng là:

42x10=420

=2x40

=80

e. = 12 - 25 + 38 + 25 - 38 + 88  - 250 

    = ( -25 + 25) + (38 - 38) + ( 12 + 88) - 250

   = -150

f. = (-12).44 + 44.(-88)

 = 44 ( -12 -88 )

= 44 . 100

= 4400

g. = -48 + 54 -77 -24 + 48 + 77

= (-48 + 48) + (-77+77) + (54 -24)

= 30

h. = 11.(-42) + 11.(-26) + 42.11 + 42.26 -26.11 - 42.26

 = \([11.\left(-42\right)+11.42]+\left[11.\left(-26\right)-26.11\right]+[42.26-42.26]\)

= 11. (-52)

= - 572

\(e.-\left(-12+25-38\right)+\left(25-38+88\right)-250\\ =12-25+38+25-38+88-250\\ =\left(25-25\right)+\left(38-38\right)+\left(12+88\right)-250\\ =0+0+100-250=-150\)

\(f.\left(-12\right)\cdot\left(67-23\right)+44\cdot\left(-88\right)\\ =\left(-12\right)\cdot44+44\cdot\left(-88\right)\\ =44\cdot\left[-12+\left(-88\right)\right]\\ =44\cdot\left(-100\right)=-4400\)

\(g.\left(-48+54-77\right)-\left(24-48-77\right)\\ =-48+54-77-24+48+77\\ =\left(48-48\right)+\left(54-24\right)+\left(77-77\right)\\ =0+30+0=30\)

\(h.11\cdot\left(-42-26\right)+42\cdot\left(11+26\right)-26\cdot11-42\cdot26\\ =11\cdot\left(-68\right)+42\cdot37-26\cdot11-42\cdot26\\ =-748+1554-286-1092=-572\)

Ta có: `A = 1 + 4 + 4^2 + 4^3 + 4^4 + 4^5 + 4^6 + 4^7 + 4^8`

`= (1 + 4 + 4^2) + (4^3 + 4^4 + 4^5) + (4^6 + 4^7 + 4^8)`

`= 21 + 4^3 (1 + 4 + 4^2) + 4^6 (1 + 4 + 4^2)`

`= 21 + 4^3 . 21 + 4^6 . 21`

`= 21 (1 + 4^3 + 4^6)`

Vì \(21\left(1+4^3+4^6\right)⋮3\) nên \(A⋮3\)

50- 49+48-47+46-45+44-43+....+4-3+2-1

= 1 + 1 + 1+ 1 + ... + 1 + 1

= 1 x 25

= 25 

mk giống của bn kia nhá

44 + 45 + 46 + 47 + 48 + 49 + 50 + 51

= \(\left[\left(51-44\right):1+1\right].\left(\frac{51+44}{2}\right)\)

= \(8.\frac{95}{2}\)

= \(380\)

Vậy 44 + 45 + 46 + 47 + 48 + 49 + 50 + 51 = 380 

giúp mình đi mà!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!