3^x+3^(x+1)+3^(x+2)=1053 <=> 3^x+3^1*3^x+3^2*3^x=1053 
<=> (1+3^1+3^2)*3^x=1053 
<=>3^x= 1053/ (1+3+9) 
<=> 3^x=81 
=> x=4

3^x+2+3^x+1+3^x=1053

=> 3^x.(3²+3+1)=1053

=> 3^x.13=1053

=> 3^x=1053:13

=> 3^x=81

=> 3^x=3⁴

Vậy x=4.

3^x+3^x+1+3^x+2=1053

=>3^x+3^x.3¹+3^x.3²=1053

=>3^x.(1+3+9)=1053

=>3^x.13=1053

=>3^x=1053:13=81

=>3^x=3⁴=>x=4

Vậy x=4

mơn ạ

\(a,3^{x-1}+3^x+3^{x+1}=1053\\ \Leftrightarrow3^x.\dfrac{1}{3}+3^x+3^x.3=1053\\ \Leftrightarrow3^x\left(\dfrac{1}{3}+1+3\right)=1053\\ \Leftrightarrow\dfrac{3^x.13}{3}=1053\\ \Leftrightarrow3^x=243\\ \Leftrightarrow3^x=3^5\\ \Leftrightarrow x=5\)

\(b,\left(x+3\right)^5=\left(x+3\right)^7\\ \Leftrightarrow\left(x+3\right)^7-\left(x+3\right)^5=0\\ \Leftrightarrow\left(x+3\right)^5\left(\left(x+3\right)^2-1\right)=0\\ \Leftrightarrow\left\{{}\begin{matrix}\left(x+3\right)^5=0\\\left(x+3\right)^2-1=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x+3-0\\\left(x+3\right)^2=1\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=-3\\x+3=\pm1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-3\\x\in\left\{-4;-2\right\}\end{matrix}\right.\)

a) (2x+1)^3=9 .81=729

=> (2x+1)=9

=> 2x=8=>x=4

b).........?

c) x=5 hoặc 6

d) .....?

e có đánh thiếu ko cj nghĩ chỗ -√x+3 này phải đánh thêm mũ 2?

cái gạch đầu dòng ko phải dấu âm đâu chị em viết dấu gạch đầu dòng chị hiểu nhầm nhé    

a: =>(3/2-2x):2/3=1/6

=>3/2-2x=1/6x2/3=2/18=1/9

=>2x=25/18

hay x=25/36

b: \(\Leftrightarrow2x-2x+\dfrac{5}{2}-2=x-\dfrac{1}{4}\)

=>x-1/4=1/2

=>x=3/4

c: \(\Leftrightarrow2x-\dfrac{2}{3}-\dfrac{1}{3}x+\dfrac{1}{4}x=0\)

=>23/12x=2/3

=>x=8/23