7574675

Lời giải:

\(\left\{x^2-[8^2-(5^2-8.3)^3-7.9]^3-4.12\right\}^3=1\\ \Rightarrow x^2-[8^2-(5^2-8.3)^3-7.9]^3-4.12=1\\ \Rightarrow x^2-(64-1-63)^3-48=1\\ \Rightarrow x^2-48=1\\ \Rightarrow x^2=49=7^2=(-7)^2\\ \Rightarrow x=\pm 7\)

\(\left\{x^2-\left[8^2-\left(5^2-8.3\right)^3-7.9\right]^3-4.12\right\}^3=8000.\)

\(\Rightarrow\left\{x^2-\left[8^2-\left(25-24\right)^3-7.9\right]^3-4.12\right\}^3=8000\)

\(\Rightarrow\left\{x^2-\left[8^2-\left(25-24\right)^3-63\right]^3-48\right\}^3=8000\)

\(\Rightarrow\left\{x^2-\left[64-1-63\right]-48\right\}^3=8000\)

\(\Rightarrow\left(x^2-48\right)^3=8000\)\(\Rightarrow x^2-48=20\)

\(\Rightarrow x^2=68\)\(\Rightarrow x=2\sqrt{17}\)

1/4.12/13+1/4.1/13-3/25

1/4.(12/13+1/13)-3/25

1/4.1-3/25

1/4-3/25

1/8

\(\frac{1}{4}\cdot\frac{12}{13}+\frac{1}{4}\cdot\frac{1}{13}-12\%=\frac{1}{4}\cdot\frac{12}{13}+\frac{1}{4}\cdot\frac{1}{13}-\frac{3}{25}=\frac{1}{4}\cdot\left(\frac{12}{13}+\frac{1}{13}\right)-\frac{3}{25}\)

\(=\frac{1}{4}\cdot1-\frac{3}{25}=\frac{1}{4}-\frac{3}{25}=\frac{13}{100}\)

Nhớ bài đây sửa đi sửa lại cũng vì do cái số " % " :(((

a) \(\left|\frac{2}{5}:x\right|=\frac{1}{4}\)

Trường hợp 1 : \(\frac{2}{5}\) : x = \(\frac{1}{4}\)

=> x = \(\frac{2}{5}:\frac{1}{4}=\frac{2}{5}\cdot4=\frac{8}{5}\)

Trường hợp 2 : \(\frac{2}{5}:x=-\frac{1}{4}\)

=> \(x=\frac{2}{5}:\left(-\frac{1}{4}\right)=\frac{2}{5}\cdot\left(-4\right)=-\frac{8}{5}\)

Vậy \(x=\pm\frac{8}{5}\)

b) \(\frac{x}{24}=-\frac{1}{3}-\frac{1}{8}=-\frac{11}{24}\)

=> x = -11

c) \(\frac{3}{x+3}=\frac{-7}{21}\)

=> \(\frac{3}{x+3}=\frac{-1}{3}\)

=> -1(x + 3) = 9

=> -x - 3 = 9

=> -x = 12

=> x = -12

\(30-\left[4\left(x-2\right)+15\right]=3\)                                                \(\left(8x-120:4\right).3^3=3^6\)

\(4\left(x-2\right)+15=27\)                                                            \(\left(8x-120:4\right)=27\)

\(4\left(x-2\right)=12\)                                                                               \(8x-30=27\)

\(x-2=3\)                                                                                          \(8x=57\)

\(x=5\)                                                                                                        \(x=\frac{57}{8}\)

15: \(\Leftrightarrow\left\{x^2-\left[8^2-\left(25-24\right)^3-63\right]^3-48\right\}=1\)

\(\Leftrightarrow x^2-48=1\)

=>x=7 hoặc x=-7

Bài 1

a) 15 + 4.12 - 3²

=15 + 48 - 9

= 63 - 9

= 54

b) {[(37 + 13) : 5].2 - 45 : 5}.7 - 2022⁰

= [(50 : 5).2 - 9].7 - 1

= (10.2 - 9).7 - 1

= (20 - 9).7 - 1

= 11.7 - 1

= 77 - 1

= 76

Bài 2

a) 13x + 3 = 16

13x = 16 - 3

13x = 13

x = 13 : 13

x = 1

b) 2x - 138 = 2⁴ : 2³

2x = 2 + 138

2x = 140

x = 140 : 2

x = 70

2a/ 2^{x - 3} = 16  => 2^{x - 3} = 2⁴  => x - 3 = 4  => x = 7

b/ {x² - [8² - (5² - 8.3)³ - 7.9]³ - 4.12}³ = 1

=> x² - [8² - (5² - 8.3)³ - 7.9]³ - 4.12 = 1

=> x² - [64 - (25 - 8.3)³ - 7.9]³ = 1 + 4.12 = 49

=> x² - (64 - 1³ - 63)³ = 49

=> x² - 0 = 49

=> x² = 49 

=> x = 7