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( 36 + 79 ) + ( 145 - 79 - 36 )
= 115 + ( 66 - 36 )
= 115 + 30
= 145
10 - [ 12 - ( - 9 - 1 ) ]
= 10 - [ 12 - ( - 10 ) ]
= 10 - 22
= - 12
( 38 - 29 + 43 ) - ( 43 + 38 )
= ( 9 + 43 ) - 81
= 52 - 81
= - 29
271 - [ ( 43 ) + 271 - ( - 17 ) ]
= 271 - [ 314 - ( - 17 ) ]
= 271 - 331
= - 60
- 144 - [ 29 - ( + 144 ) - ( + 144 ) ]
= - 144 - [ ( - 115 ) - ( + 144 ) ]
= - 144 - ( - 259 )
= 115
(36+79)+(145-79-36)
=115+30
=145
10-[12-(-9-1)]
=10-22
=-12
(38-29+43)-(43+38)
=52-81
=(-29)
271-[(43)+271-(17)]
=271-297
=(-26)
-144-[29-(+144)-(+144)
=-144-(-259)
=115
a, (38 - 29 + 43) - (43 + 38)
= 38 - 29 + 43 - 43 - 38
= (38 - 38) + (43 - 43) - 29
= -29
b, 271 - [(-43) + 271 - (-17)]
= 271 - (-43 + 271 + 17)
= 271 + 43 - 271 - 17
= (271 - 271) + (43 - 17)
= 26
@Dương Taurus
c, (-11)2.3 - [3 - (-50).(-4)]
= 121.3 - [(3 + 50.(-4)]
= 363 - 3 + 200
= 560
d, 4.52 + 81.32 - (13 - 4)2
= 4.25 + 81.9 - 132 + 42
= 100 + 729 - 169 + 16
= 676
@Dương Taurus
27 + 514 - 486 + 73 = 128
10 - 12 - 9 - 1 = - 12
Tk mik mik làm nốt cho
Mik mới bị trừ 50 chục điểm bùn qúa T_T
a . 25 − 58 − 9 = - 31 b . 1 − ( 26 + 3 ) = - 28 c . 12.15 − 12.5 = 120 d . 10 − [ 12 − ( − 9 − 1 ) ] = -12 e . ( 38 − 29 + 43 ) − ( 43 + 38 ) = - 29 f . 2575 + 37 − 2576 − 29 = 7
f,(36+79)+(145-79-36)
=36+79+145-79-36
=(36-36)+(79-79)+145
=0+0+145
=145
g,10-[12-(-9-1)]
=10-(12+9+1)
=10-(12+10)
=10-12-10
=(10-10)-12
=0-12
=-12
h,(38-29+43)-(43+38)
=38-29+43-43-38
=(38-38)-29+(43-43)
=0-29+0
=-29
i,271-[(-43)+271-(-17)]
=271-(-43+271+17)
=271+43-271-17
=(271-271)+(43-17)
=0+26
=26
k,-144-[29-(+144)-(+144)]
=-144-(29-144-144)
=-144-29+144+144
=(-144+144)-29+144
=0-29+144
=-29+144
=115
-5-9-11-24
=-14-11-24
=-25-24
=-49
-14-7-12-24
=-21-12-24
=-33-24
=-57
12+38-30-22
=50-30-22
=20-22
=-2
34+(-43)+66-55
=-9+66-55
=57-55
=2
-10-14-16+43
=-24-16+43
=-40+43
=3
4
1
62
31
321
3132132
3145461320...................22222222222222222222222223130
2222222222222222222222222222222222226
30.
3062+958*+96
33
.36+9.03693
.36363.
\(=-43\cdot\left(38+12-50\right)=-43\cdot0=0\)
=-43.(38+12+50)
=-43.0
=0