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a) (x – 35).35 = 35 ó x – 35 = 1 ó x = 36
b) 43.(x – 19) = 86 ó x – 19 = 2 ó x = 21
c) (x + 7).34 = 2.34 ó x + 7 = 2
Điều này không xảy ra khi x là số tự nhiên. Vậy không có giá trị nào của x thỏa mãn
45 . ( 2.x - 4 ) . 13 = 0
45 . 13 . ( 2.x - 4 ) = 0
585 . ( 2.x - 4 ) = 0
( 2.x - 4 ) = 0 : 585
2.x - 4 = 0
2.x = 0 + 4
2.x = 4
x = 4 : 2
x = 2
( x + 7 ) . 35 = 2.35
x + 7 = ( 2 . 35 ) : 35
x + 7 = 35
x = 35 - 7
x = 28
43 . ( x - 19 ) = 86
x - 19 = 86 : 43
x - 19 = 2
x = 2 + 19
x = 21
9: \(=\dfrac{47}{51}\cdot\dfrac{17}{94}-\dfrac{47}{51}\cdot\dfrac{53}{91}-\dfrac{53}{91}\cdot\dfrac{91}{53}+\dfrac{53}{91}\cdot\dfrac{47}{51}\)
\(=\dfrac{1}{6}-1=-\dfrac{5}{6}\)
10: \(=\dfrac{13}{19}\cdot\dfrac{19}{26}-\dfrac{13}{19}\cdot\dfrac{71}{43}+\dfrac{71}{43}\cdot\dfrac{13}{19}-\dfrac{71}{43}\cdot\dfrac{86}{71}\)
\(=\dfrac{1}{2}-2=-\dfrac{3}{2}\)
Thôi, để mk giải chi tiết cho, không lại bảo mk lười:
A=\(\dfrac{18}{26}+\dfrac{-5}{27}+\dfrac{-22}{86}+\dfrac{12}{39}+\dfrac{-32}{43}\)
A=\(\dfrac{9}{13}+\dfrac{-5}{27}+\dfrac{-11}{43}+\dfrac{4}{13}+\dfrac{-32}{43}\)
A=\(\left(\dfrac{9}{13}+\dfrac{4}{13}\right)+\left(\dfrac{-11}{43}+\dfrac{-32}{43}\right)+\dfrac{-5}{27}\)
A= 1+(-1)+\(\dfrac{-5}{27}\)
A=0+\(\dfrac{-5}{27}\)
A=\(\dfrac{-5}{27}\)
B=\(\dfrac{-10}{12}+\dfrac{8}{15}+\dfrac{-19}{56}+\dfrac{-3}{18}+\dfrac{28}{60}\)
B=\(\dfrac{-5}{6}+\dfrac{8}{15}+\dfrac{-19}{56}+\dfrac{-1}{6}+\dfrac{7}{15}\)
B=\(\left(\dfrac{-5}{6}+\dfrac{-1}{6}\right)+\left(\dfrac{8}{15}+\dfrac{7}{15}\right)+\dfrac{-19}{56}\)
B= -1+1+\(\dfrac{-19}{56}\)
B=0+\(\dfrac{-19}{56}\)
B=\(\dfrac{-19}{56}\)
Ôi mỏi quá! Chúc bạn học tốt !
A = \(\dfrac{18}{26}\) + (-\(\dfrac{5}{27}\)) + (-\(\dfrac{22}{86}\)) + \(\dfrac{12}{39}\) - \(\dfrac{32}{43}\)
A = \(\dfrac{9}{13}\) - \(\dfrac{5}{27}\) - \(\dfrac{11}{43}\) + \(\dfrac{4}{13}\) - \(\dfrac{32}{43}\)
A = (\(\dfrac{9}{13}\) + \(\dfrac{4}{13}\)) - (\(\dfrac{11}{43}\) + \(\dfrac{32}{43}\)) - \(\dfrac{5}{27}\)
A = \(\dfrac{13}{13}\) - \(\dfrac{43}{43}\) - \(\dfrac{5}{27}\)
A = 1 - 1 - \(\dfrac{5}{27}\)
A = 0 - \(\dfrac{5}{27}\)
A = - \(\dfrac{5}{27}\)
a, \(\left(-23\right).43+\left(-23\right).65-\left(-23\right).8\\ =\left(-23\right).\left(43+65-8\right)\\ =\left(-23\right).100=-2300\)
b,\(\left(-43\right).25+25.\left(-19\right)+25.\left(-38\right)\\ =25.\left[\left(-43\right)+\left(-19\right)+\left(-38\right)\right]\\ =25.\left(-100\right)=-2500\)
c,\(\left(-26\right).13+86.\left(-26\right)+\left(-26\right)\\ =\left(-26\right).\left(13+86+1\right)\\ =\left(-26\right).100=-2600\)
d,\(\left(-17\right).39+\left(-17\right)+\left(-17\right).60\\ =\left(-17\right).\left(39+1+60\right)\\ =\left(-17\right).100=-1700\)
a) (-32) . 43 + (-32) . 65 - (-32) . 8
= (-32) . (43 + 65 - 8)
= (-32) . 100
= -3200
b) (-43) . 25 + 25 . (-19) + 25 . (-38)
= 25 . [(-43) + (-19) + (-38)]
= 25 . (-100)
= -2500
c) (-26) . 13 + 86 . (-26) + (-26)
= (-26) . (13 + 86 + 1)
= (-26) . 100
= -2600
d) (-17) . 39 + (-17) + (-17) . 60
= (-17) . (1 + 39 + 60)
= (-17) . 100
= -1700
43.(x-19)=86
x-19=2
x=21
\(43\times\left(x-19\right)=86\)
\(x-19=86\div43\)
\(x-19=2\)
\(x=2+19\)
\(x=21\)
@#$%^&* !