\(=\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(3\cdot5^2\right)^{15}}=\dfrac{3^{20}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot5^{30}}=3^5=243\)

\(\frac{45^{10}\cdot5^{20}}{75^{15}}=\frac{9^{10}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot25^{15}}=\frac{3^{20}\cdot5^{30}}{3^{15}\cdot5^{30}}=3^5\)

\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{\left(5.3^2\right)^{10}.5^{20}}{\left(5^2.3\right)^{15}}=\dfrac{5^{21}.3^{20}}{5^{30}.3^{15}}=\dfrac{1.3^5}{5^9.1}=\dfrac{3^5}{5^9}\)

Mk làm hơi tắt còn kết quả mk vẫn để lũy thừa vì nếu => số

Chúc bn học tốt

\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}\\ =\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(5^2\cdot3\right)^{15}}\\ =\dfrac{\left(3^2\right)^{10}\cdot5^{10}\cdot5^{20}}{\left(5^2\right)^{15}\cdot3^{15}}\\ =\dfrac{3^{20}\cdot5^{30}}{5^{30}\cdot3^{15}}\\ =3^5\\ =243\)

Đề bài là gì vậy ?

Giải:

\(\dfrac{45^{10}.5^{20}}{75^{15}}\)

\(=\dfrac{\left(3.3.5\right)^{10}.5^{20}}{\left(3.5.5\right)^{15}}\)

\(=\dfrac{3^{10}.3^{10}.5^{10}.5^{20}}{3^{15}.5^{15}.5^{15}}\)

\(=\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}\)

\(=3^5=243\)

Vậy giá trị của biểu thức trên là 243.

Chúc bạn học tốt!!!

\(\dfrac{45^{10}.5^{20}}{75^{15}}=\dfrac{3^{20}.5^{30}}{3^{15}.5^{30}}=3^5=243\)

Ta có : \(\frac{45^{10}.5^{20}}{75^{15}}=\frac{9^{10}.5^{10}.5^{20}}{3^{15}.25^{15}}=\frac{\left(3^2\right)^{10}.5^{30}}{3^{15}.\left(5^2\right)^{15}}=\frac{3^{20}.5^{30}}{3^{15}.5^{30}}=3^5\)

\(\frac{45^{10}.5^{20}}{75^{15}}=\frac{\left(3^2.5\right)^{10}.5^{20}}{\left(3.5^2\right)^{15}}=\frac{3^{20}.5^{10}.5^{20}}{3^{15}.5^{30}}\)

                   \(=\frac{3^{20}.5^{30}}{3^{15}.5^{30}}=\frac{3^5.1}{1.1}=3^5=243\)

\(\frac{45^{10}\cdot5^{20}}{75^{15}}=\frac{3^{20}\cdot5^{30}}{3^{15}\cdot5^{30}}=3^5=243\)