`(4x-1)^3=27`

`=>(4x-1)^3=3^3`

`=>4x-1=3`

`=>4x=4=>x=1`

Vậy `x=1`

     \(\left(4x-1\right)^3=27\)

⇔ \(\left(4x-1\right)^3=3^3\)

⇒      \(4x-1=3\)

⇔             \(x=1\)

\(\dfrac{3x-4}{4}=\dfrac{4x-8}{5}\)

\(\Leftrightarrow\dfrac{3x-4}{4}-\dfrac{4x-8}{5}=0\)

\(\Leftrightarrow\dfrac{5\left(3x-4\right)}{20}-\dfrac{4\left(4x-8\right)}{20}=0\)

\(\Leftrightarrow\dfrac{15x-20}{20}-\dfrac{16x-32}{20}=0\)

\(\Leftrightarrow\dfrac{15x-20-16x+32}{20}=0\)

\(\Leftrightarrow\dfrac{x-12}{20}=0\)

\(\Leftrightarrow x-12=0\)

\(\Leftrightarrow x=12\)

4x : 17 = 0

=> 4x = 0

x = 0 : 4

x = 0

Vậy x = 0

8(x - 3) = 0

=>  x - 3 = 0

x = 0 + 3

x = 3

Vậy x = 3

4x : 17 = 0

4x        = 0 x 17

4x        =    0

  x        = 0 : 4

  x        =   0

8( x - 3 ) = 0

  ( x - 3 ) = 0 : 8

    x - 3    =  0

    x         = 0 + 3

    x         =   3

\(4x+3.\left(1-x\right)=2.\left(x-2\right)\)

\(4x+3-3x=2x-4\)

\(\left(4x-3x\right)+3=2x-4\)

\(x+3=2x-4\)

\(x-2x=-4-3\)

\(-x=-7\)

\(x=7\)

4x - 15 = 3^2.5

4x - 15 = 3¹⁰ 

4x       = 3¹⁰ + 15

4x       = 59064

 x        = 59064 : 4

 x        = 14766

\(4x-15=3^2.5\)

\(4x-15=9.5\)

\(4x-15=45\)

\(\Rightarrow4x=45+15\)

\(\Rightarrow4x=60\)

\(\Rightarrow x=15\)

xy+4x=25+5y
=> xy-5y+4x-20=5
=> y.(x-5)+4.(x-5)=5
=>(x-5)(y+4)=5
=> x-5 và y+4 là ước của 5 = {1;-1;5;-5}
Tự giải tiếp ...

7 (x-3)=3x-1

7x -21=3x -1

7x +3x =-1 +21

10x=20

x=20:10=2

Thank bn vì lời chúc, bn cute thiệt ó ^^!