\(-\frac{1}{4}x+\frac{3}{2}x-\frac{2}{3}x+6=\)\(0\)

\(\Rightarrow\)\(-\frac{1}{4}x+\frac{3}{2}x-\frac{2}{3}x\)\(=-6\)

\(\Rightarrow\)\(x\left(-\frac{1}{4}+\frac{3}{2}-\frac{2}{3}\right)\)\(=-6\)

\(\Rightarrow\)\(x.\frac{7}{12}\)\(=-6\)

\(\Rightarrow\)\(x\)\(=-\frac{72}{7}\)

\(\text{Học tốt!!!}\)

=>(2x-7)²⁼9

=>2x-7 =3 hoặc 2x-7=-3

=>2x=10 hoặc 2x=4

=>x=5 hoặc x=2

    Vậy ....................

\(2\cdot\left(2x-7\right)^2=18\)

\(\Rightarrow\left(2x-7\right)^2=9\)

\(\Rightarrow\hept{\begin{cases}2x-7=3\\2x-7=-3\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}2x=10\\2x=4\end{cases}\Rightarrow}\hept{\begin{cases}x=5\\x=2\end{cases}}\)

\(\frac{1}{2}\times\left(x-\frac{4}{5}\right)+\frac{3}{4}x=\frac{5}{12}\)

\(\Leftrightarrow\frac{1}{2}x-\frac{2}{5}+\frac{3}{4}x=\frac{5}{12}\)

\(\Leftrightarrow\frac{1}{2}x+\frac{3}{4}x=\frac{5}{12}+\frac{2}{5}\)

\(\Leftrightarrow\frac{5}{4}x=\frac{49}{60}\)

\(\Leftrightarrow x=\frac{49}{75}\)

Vậy \(x=\frac{49}{75}\)

bạn ơi sao lại có 2/5 vâỵ

=>2x+1/2=0 hoặc 2x-3=0

=>x=-1/4 hoặc x=3/2

\(\left[{}\begin{matrix}\dfrac{1}{2}+2x=0\\2x-3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=-\dfrac{1}{2}\\2x=3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{4}\\x=\dfrac{3}{2}\end{matrix}\right.\)

(2x+1)(y+2)=4

⇒(2x+1) và (y+2) ∈ Ư (4) = { 1,-1,2,-2,4,-4 }

⇒2x+1=1        ⇒2x=1-1=0            ⇒x=0:2=0

   y+2=4             y=4-2=2                  y=2

⇒2x+1=-1      ⇒2x=-1-1=-2        ⇒x=-2:2=-1

   y+2=-4           y=-4-2=-6             y=-6

⇒2x+1=2        ⇒2x=2-1=1          ⇒x=1:2=0,5

   y+2=-2           y=-2-2=-4             y=-4

\(\left(2x-1\right)\left(y-2\right)=4\)

\(\Rightarrow2x-1\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)

Mà \(2x+1\) lẻ

\(\Rightarrow2x+1=\pm1\)

Xét \(2x+1=1\Rightarrow x=0\)

\(\Rightarrow y-2=4\Rightarrow y=6\)

Xét \(2x+1=-1\Rightarrow x=-1\)

\(\Rightarrow y-2=-4\Rightarrow y=-2\)

\(\Leftrightarrow-\dfrac{2}{5}\left(4x-3\right)^2=-\dfrac{5}{18}\)

\(\Leftrightarrow\left(4x-3\right)^2=\dfrac{25}{36}\)

\(\Leftrightarrow4x-3\in\left\{\dfrac{5}{6};-\dfrac{5}{6}\right\}\)

hay \(x\in\left\{\dfrac{23}{24};\dfrac{13}{24}\right\}\)

a. 8 . 2x - 5 - 32 = 119

8 . 2x - 5 - 9 = 119

8 . 2x - 5 = 119 + 9

8 . 2x - 5 = 128

2x - 5 = 128 : 8

2x -  5 = 16

2x -  5 = 24 (cùng cơ số)

x - 5 = 4

x = 4 + 5; x = 9

b. 5x + 2x = 62 - 50

7x = 36 - 1

7x = 35

x = 5

a. 8 . 2^{x - 5} - 3² = 119

8 . 2^{x - 5} - 9 = 119

8 . 2^{x - 5} = 119 + 9

8 . 2^{x - 5 =} 128

2^{x - 5} = 128 : 8

2^{x -  5} = 16

2^{x -  5} = 2⁴ (cùng cơ số)

x - 5 = 4

x = 4 + 5; x = 9

b. 5x + 2x = 6² - 5⁰

7x = 36 - 1

7x = 35

x = 6

\(\dfrac{3x-4}{4}=\dfrac{4x-8}{5}\)

\(\Leftrightarrow\dfrac{3x-4}{4}-\dfrac{4x-8}{5}=0\)

\(\Leftrightarrow\dfrac{5\left(3x-4\right)}{20}-\dfrac{4\left(4x-8\right)}{20}=0\)

\(\Leftrightarrow\dfrac{15x-20}{20}-\dfrac{16x-32}{20}=0\)

\(\Leftrightarrow\dfrac{15x-20-16x+32}{20}=0\)

\(\Leftrightarrow\dfrac{x-12}{20}=0\)

\(\Leftrightarrow x-12=0\)

\(\Leftrightarrow x=12\)

\(a,\Rightarrow x+2=-40\\ \Rightarrow x=-42\\ b,\Rightarrow6x-7-2x=5\\ \Rightarrow4x=12\Rightarrow x=3\\ c,\Rightarrow68-56-x=-2\\ \Rightarrow12-x=-2\\ \Rightarrow x=14\)