có ai biết bài này không xin trả lời dùm 

18 chia 2phaan 3

   [4\(\dfrac{1}{5}\) - 2\(\dfrac{2}{5}\)] x 8\(\dfrac{5}{6}\)

= [\(\dfrac{21}{5}\) - \(\dfrac{12}{5}\)] x \(\dfrac{53}{6}\)

= \(\dfrac{9}{5}\) x \(\dfrac{53}{6}\)

= \(\dfrac{159}{10}\)

   [5\(\dfrac{1}{3}\) - 2\(\dfrac{2}{3}\)]: \(\dfrac{3}{7}\)

= [\(\dfrac{16}{3}\) - \(\dfrac{8}{3}\)]: \(\dfrac{3}{7}\)

= \(\dfrac{8}{3}\) : \(\dfrac{3}{7}\)

= \(\dfrac{56}{9}\)

\(\frac{2}{3}\)x \(\frac{5}{8}\)x \(\frac{8}{15}\)= \(\frac{2}{3}\)x \(\frac{1}{15}\)= \(\frac{2}{45}\)

\(\frac{22}{5}\)x \(12\)x \(\frac{20}{40}\)= \(\frac{22}{5}\)x \(12\)x \(\frac{1}{2}\)= \(\frac{22}{5}\)x 6 = \(\frac{122}{5}\)

\(\frac{7}{2}\)x \(\frac{26}{7}\)x \(\frac{4}{13}\)= \(\frac{91}{7}\)x \(\frac{4}{13}\)

Câu 1:

a. $3\frac{2}{3}+2\frac{1}{2}=(3+2)+(\frac{2}{3}+\frac{1}{2})=5+\frac{7}{6}=6+\frac{1}{6}=6\frac{1}{6}$

b. \(2\frac{1}{2}\times 3\frac{2}{5}=\frac{5}{2}\times \frac{17}{5}=\frac{17}{2}\)

c.

\(3\frac{1}{3}: 4\frac{1}{4}=\frac{10}{3}: \frac{17}{4}=\frac{40}{51}\)

d.

\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}=(3+4-5)+(\frac{1}{2}+\frac{5}{7}-\frac{5}{14})=2+\frac{6}{7}=2\frac{6}{7}\)

Câu 2:

a. $x\times \frac{2}{7}=\frac{6}{11}$

$x=\frac{6}{11}: \frac{2}{7}=\frac{21}{11}$

b. $x: \frac{3}{2}=\frac{1}{4}$

$x=\frac{1}{4}\times \frac{3}{2}=\frac{3}{8}$

giúp mình với các bạn ơi

3/4 x 8/5 x 5/9 = 3/4 x 8/5 x 5/9 = 1/1 x 2/1 x 1/3 = 2/3 

6/4 : 3/14 : 1/2 = 6/4 x 14/3 x 2/1 = 2/2 x 14/1 x 1/1 = 14 

k mk nha

3/4×8/5×5/9=2/3

6/4:3/14:1/2=14

Gọi số đó là a. => a+1 chia hết cho 2;3;4;5;6;7;8;9;10 => a+1 thuộc BC(2;3;4;5;6;7;8;9;10) nhưng vì a nhỏ nhất nên a+1 = BCNN(2;3;4;5;6;7;8;9;10)=2520 => a = 2520 -1 => a = 2519

goi so do la a=> a+1 chia het 2345678910 a+1 thuoc bc 2345678910 vi anho nhat suy ra bcnn 2345678910 =2520 +1 Phai - 1 suy ra a-1 = 2519