Ta có: 100 < 52x – 1 < 56

=> 52 < 100 < 52x-1 < 56

=> 2 < 2x – 1 < 6

=> 2 + 1 < 2x < 6 + 1

=> 3 < 2x < 7

Vì x ∈ N nên suy ra: x ∈ {2; 3} là thỏa mãn.

Ta có 100=5².4

\(\Rightarrow5^3\le5^{2x-1}< 5^6\)

\(\Rightarrow3\le2x-1< 6\)

\(\Rightarrow4\le2x< 7\)

\(\Rightarrow2\le x< 3,5\)

Mà \(x\) là số tự nhiên

\(\Rightarrow x=2\) hoặc \(x=3\)

\(5^{2x-1}=125\cdot5^4\)

\(\Leftrightarrow2x-1=7\)

hay x=4

x=3

\(\Rightarrow5^{2x-3}=5^2\cdot3+5^2\cdot2=5^2\cdot5=5^3\\ \Rightarrow2x-3=3\\ \Rightarrow x=3\)

5^2x-3-10=75

5^2x-3=85

\(5^{2x-3}-2.5^2=5^2.3\)

\(\Rightarrow5^{2x-3}-50=75\)

\(\Rightarrow5^{2x-3}=125=5^3\)

\(\Rightarrow2x-3=3\Rightarrow2x=6\Rightarrow x=3\)

Tham Khảo]

(5^2x.5^x+2) : 25 = 125²

5^2x.5^x+2 = 125².25 = 5⁶.5²

5^2x+x+2 = 5⁸

5^3x+2 = 5⁸

=> 3x + 2 = 8

=> 3x = 6

=> x = 2

\(5^{2x+1}.5^{x+1}=5^{17}\)

\(\Rightarrow5^{2x+1+x+1}=5^{17}\)

\(\Rightarrow5^{3x+2}=5^{17}\)

\(\Rightarrow3x+2=17\)

\(\Rightarrow3x=15\Rightarrow x=5\)

5²ˣ⁻³ - 2.5² = 5².3

5²ˣ⁻³ - 2.25 = 25.3

5²ˣ⁻³ - 50 = 75

5²ˣ⁻³ = 75 + 50

5²ˣ⁻³ = 125

5²ˣ⁻³ =5³

2x - 3 = 3

2x = 3 + 3

2x = 6

x = 6 : 2

x = 3

\(5^{2x-3}-2.5^2=5^2.3\)

\(\Leftrightarrow5^{2x}:5^3-50=75\)

\(\Leftrightarrow5^{2x}:5^3=75+50\)

\(\Leftrightarrow5^{2x}:5^3=125\)

\(\Leftrightarrow5^{2x}=125.5^3\)

\(\Leftrightarrow5^{2x}=5^3.5^3\)

\(\Leftrightarrow5^{2x}=5^6\)

\(\Leftrightarrow2x=6\)

\(\Leftrightarrow x=6:2\)

\(\Leftrightarrow x=3\)

Vậy x=3

5²ˣ⁻³ - 2.5² = 5².3

5²ˣ⁻³ - 2.25 = 25.3

5²ˣ⁻³ - 50 = 75

5²ˣ⁻³ = 75 + 50

5²ˣ⁻³ = 125

5²ˣ⁻³ = 5³

2x - 3 = 3

2x = 3 + 3

2x = 6

x = 6 : 2

x = 3

alo ạ

\(5^{2x+1}\cdot5^{2x+2}-5^x\cdot5^{3x+2}=100\)

\(\Leftrightarrow5^{4x+3}-5^{4x+2}=100\)

\(\Leftrightarrow625^x\left(5^3-5^2\right)=100\)

\(\Leftrightarrow625^x=1\)

hay x=0

\(\Rightarrow5^{2x+1+2x+2}-5^{x+3x+2}=100\\ \Rightarrow5^{4x+3}-5^{4x+2}=100\\ \Rightarrow5^{4x+2}\left(5-1\right)=100\\ \Rightarrow5^{4x+2}=25=5^2\\ \Rightarrow4x+2=2\Rightarrow x=0\)