\(5871:\left[928-\left(247-82.5\right)\right]\)

\(=5871:\left(928+163\right)\)

\(=5871:1091\)

\(=5,381301558\)

Chúc bạn học tốt !

5871 : [ 928 – (247 – 82 x 5)]

= 5871 : [928 – (247 – 410)]

= 5871 : [928 – (-163)]

= 5871 : 1091

= 5871/1901

chúc bạn may mắn trong kì thi

\(5871:\left[928-\left(247-82.5\right)\right]\\ =5871:\left[928-\left(247-410\right)\right]\\ =5871:\left[928-\left(-163\right)\right]\\ =5871:1091\\ =\dfrac{5871}{1091}\)

5871/1091

\(=\dfrac{5871}{928-\left(247-410\right)}=\dfrac{5871}{928-247+410}\)

\(=\dfrac{5871}{1091}\)

\(5871:\left[928-\left(247-82\cdot5\right)\right]\)

\(=5871:\left[928-\left(247-410\right)\right]\)

\(=5871:\left(928+163\right)\)

\(=5871:1091\)

\(=\dfrac{5871}{1091}\)

5871 : [ 928 – (247 – 82 x 5)]

= 5871 : [928 – (247 – 410)]

= 5871 : [928 – (-163)]

= 5871 : 1091

= 5871/1901

phân tích kết quả ra thừa số nguyên tố nữa nhé bạn giúp mình với

\(=5871:\left[928-\left(247-410\right)\right]\)

\(=5871:\left(928+163\right)\)

\(=5871:1091\)

\(=\frac{5871}{1091}\)

tíc mình nha

247-410 sao chia được

5871⁰ : [928 - (247 - 82).5] + 2175⁰

= 1 : (928 - 165.5) + 1

= 1 : (928 - 825) + 1

= 1 : (-103) + 1

= 102/103

a; 4.52 - 32 : 24

= 208 - \(\dfrac{4}{3}\)

= \(\dfrac{624}{3}\) - \(\dfrac{4}{3}\)

= \(\dfrac{620}{3}\)

c; 777 : 7 + 1331 : 113

= 111 + \(\dfrac{1331}{113}\)

= \(\dfrac{12543}{113}\) + \(\dfrac{1331}{113}\)

= \(\dfrac{13874}{113}\) 

\(=5871:\left[928-165\cdot5\right]\\ =5871:\left[928-825\right]=5871:103=57\)

\(=5871:\left[928-165.5\right]=5871:\left[928-825\right]=5871:103=57\)