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Ta có:\(8^{12}=\left(2^3\right)^{12}=2^{3.12}=2^{36}\\ \\ \\ 32^6=\left(2^5\right)^6=2^{5.6}=2^{30}\) Mà \(2^{36}>2^{30}\)
⇒ Chọn A
812 = (23)12 = 236
326 = (25)6 = 230
Vì 236 > 330 ⇒ 812 > 326 ⇒ Chọn A
a) \(\frac{75^3.3^7}{81^4.5^6}=\frac{5^3.3^3.5^3.3^7}{\left(3^4\right)^4.5^6}=\frac{5^6.3^3.3^7}{3^{16}.5^6}=\frac{3^{10}}{3^{16}}=\frac{1}{3^6}=\frac{1}{729}\)
b) \(\frac{6^6.4^2}{3^{12}.2^8}=\frac{2^6.3^6.\left(2^2\right)^2}{3^{12}.2^8}=\frac{2^6.3^6.2^4}{3^{12}.2^8}=\frac{2^{10}.3^6}{3^{12}.2^8}=\frac{2^2.1}{3^6}=\frac{4}{729}\)
c) \(\frac{34^5.2^5}{2^{14}.17^5}=\frac{2^5.17^5.2^5}{2^{14}.17^5}=\frac{2^{10}}{2^{14}}=\frac{1}{2^4}=\frac{1}{16}\)
b) \(\dfrac{\left(0,8\right)^5}{\left(0,4\right)^6}\)
\(=\dfrac{\left(0,8\right)^5}{\left(0.4\right)^5\cdot0,4}\)
\(=\left(\dfrac{0,8}{0,4}\right)^5\cdot\dfrac{1}{0,4}\)
\(=2^5\cdot\dfrac{5}{2}\)
\(=\dfrac{2^5\cdot5}{2}\)
\(=2^4\cdot5\)
\(=80\)
c) \(\dfrac{2^{15}\cdot9^4}{6^6\cdot8^3}\)
\(=\dfrac{2^{15}\cdot\left(3^2\right)^4}{2^6\cdot3^6\cdot\left(2^3\right)^3}\)
\(=\dfrac{2^{15}\cdot3^8}{2^{15}\cdot3^6}\)
\(=\dfrac{3^2}{1}\)
\(=9\)
\(6^6+6^6+6^6+6^6+6^6+6^6\)
\(=\left(1+1+1+1+1+1\right)\cdot6^6\)
\(=6\cdot6^6\)
\(=6^7\)