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1+2+3+4+5+6+7+8+9+10=55
11+12+13+14+15+16+17+18+19+20=155
1+2+3+4+5+6+7+8+9+10+11+12+13+14 +15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30-50-53=362
\(1+2+3+4+5+6+7+8+9+10=55\)
\(11+12+13+14+15+16+17+18+19+20=155\)
a)1050 : 15 - 150 : 15 + 150 : 19 + 1940
=(1050 : 15 +1940) +(-150 : 15 + 150 :19 )
=(1050 : 15 +29100 : 15) - 150 : ( 15 -19 )
=(1050 + 29100) : 15 - 150 :(-4)
=30150 :15 +37,5
=2010 +37,5
=2047,5
b)53.39 + 47.39 - 53.21 - 47.21
=39(53 + 47) - 21(53 + 47)
=100(39-21)
=100.18
=1800
c)2.53.12 + 4.6.87
=24.53 + 24.87
=24(53 + 87)
=24.140
=3360
a)1050 : 15 - 150 : 15 + 150 : 19 + 1940
= (1050 : 15 +1940) +(-150 : 15 + 150 :19 )
= (1050 : 15 +29100 : 15) - 150 : ( 15 -19 )
= (1050 + 29100) : 15 - 150 :(-4)
=30150 :15 +37,5
=2010 +37,5
=2047,5
\(\frac{17}{21}\cdot\frac{48}{53}+\frac{17}{21}\cdot\frac{4}{53}+\frac{52}{53}\cdot\frac{4}{21}\)
\(=\frac{17}{21}\left(\frac{48}{53}+\frac{4}{53}\right)+\frac{52}{53}\cdot\frac{4}{21}\)
\(=\frac{17}{21}\cdot\frac{52}{53}+\frac{52}{53}\cdot\frac{4}{21}\)
\(=\frac{52}{53}\left(\frac{17}{21}+\frac{4}{21}\right)\)
\(=\frac{52}{53}\cdot1\)
\(\frac{17}{21}.\frac{48}{53}+\frac{17}{21}.\frac{4}{53}+\frac{52}{53}.\frac{4}{21}\)
= \(\frac{17}{21}.\left(\frac{48}{53}+\frac{4}{53}\right)+\frac{52}{53}.\frac{4}{21}\)
= \(\frac{17}{21}.\frac{52}{53}+\frac{52}{53}.\frac{4}{21}\)
=\(\frac{52}{53}.\left(\frac{17}{21}+\frac{4}{21}\right)\)
= \(\frac{52}{53}\)
\(\frac{8}{29}+\frac{4}{21}-53\frac{3}{53}+\frac{17}{21}-\frac{27}{19}\)
\(=\left(\frac{8}{19}-\frac{27}{19}\right)+\left(\frac{4}{21}+\frac{17}{21}\right)-53\frac{3}{53}\)
\(=-1+1-53\frac{3}{53}=0-53\frac{3}{53}=-53\frac{3}{53}\)