5x=36+4

5x=40

x=8

5x=6^17-15+4

5x=6²+4

5x=40

x=8

a: 132+2(x-4)=46

=>2(x-4)=46-132

=>2(x-4)=-86

=>\(x-4=-\dfrac{86}{2}=-43\)

=>x=-43+4=-39

b: \(9x-6^{17}:6^{15}=4x+48:12\)

=>\(9x-6^2=4x+4\)

=>9x-36=4x+4

=>9x-4x=36+4

=>5x=40

=>x=40/5=8

\(2^{x+3}.4^2=64\Leftrightarrow2^{x+3}.2^4=64\Leftrightarrow2^{x+7}=2^6\Leftrightarrow x+7=6\Leftrightarrow x=-1\)

\(132+2\left(x-4\right)=46\)
\(2\left(x-4\right)=132-46\)
\(2\left(x-4\right)=86\)
\(x-4=86:2\)
\(x-4=43\)
\(x=47\)

em cảm ơn

bạn có ghi nhầm đề ko ?

\(\dfrac{5}{-6}=\dfrac{-55}{66};\dfrac{-10}{11}=\dfrac{-60}{66}\Rightarrow\dfrac{-55}{66}>\dfrac{-60}{66}\Rightarrow\dfrac{5}{-6}>\dfrac{-10}{11}\\ \dfrac{-3}{20}=\dfrac{-45}{300};\dfrac{2}{-15}=\dfrac{-40}{300}\Rightarrow\dfrac{-45}{300}< \dfrac{-40}{300}\Rightarrow\dfrac{-3}{20}< \dfrac{2}{-15}\\ -0,305>-0,36\)

\(^\circ\) \(\dfrac{5}{-6}\) và \(\dfrac{-10}{11}\)

Ta có \(:\)

\(\dfrac{5}{-6} = \dfrac{ 5 . 11 }{ -6 . 11 } = \dfrac{ 55 }{ -66} \)

\(\dfrac{-10}{11} = \dfrac{-10 . ( -6 )}{11.(-6)} = \dfrac{60}{-66}\)

Do \(55 < 60\)

\(=> \dfrac{55}{-66} > \dfrac{60}{-66}\)

Vậy \(\dfrac{55}{-66} > \dfrac{60}{-66}\)

4x:7=0

=> 4x=0

=>x=0

7x-8=713

=> 7x= 713+8

=>7x=721

=> x=721:7 

=>x=103

tíc mình nha

mk biết bài này nhưng thấy hình của sơn tùng là mk mk ko muốn giải

\(9x-4x=6^{17}:6^{15}+48:12\\ 5x=6^2+4\\ 5x=36+4=40\\ x=8\)