#)Giải :

A, \(\frac{254x399-145}{254+399x253}\)

\(=\frac{253x399+399-145}{254+399x253}\)

\(=\frac{253x399+254}{254+399x253}\)

\(=1\)

B, \(\frac{5932+6001x5931}{5931x6001-69}\)

\(=\frac{5932+6001x5931}{\left(5931+1\right)x6001-69}\)

\(=\frac{5932+6001x5931}{5931x6001+6001-69}\)

\(=\frac{5932+6001x5932}{5932x6001+5932}\)

\(=1\)

         #~Will~be~Pens~#

\(\frac{254x399-145}{254+399x253}=\frac{\left(253+1\right)x399-145}{254+399x253}=\frac{253x399+1x399-145}{254+399x253}=\frac{253x399+254}{254+399x253}\)

\(=1\)

3*x + 2*x + x =12*5 + 12*4 + 12

3*x +2*x + x = 12*(5 + 4 +1)

3*x + 2*x + x = 12*10

3*x + 2*x + x = 120

x*(3 +2 + 1) = 120

x*6              = 120

x                  = 120 : 6

x                   = 20

=202292,4331 nha bạn

liên tục dng ko

=2022924291

\(\frac{3}{4}.\frac{12}{7}+x=\frac{5}{2}\)

\(\frac{3.3}{1.7}+x=\frac{5}{2}\)

\(\frac{9}{7}+x=\frac{5}{2}\)

\(x=\frac{5}{2}-\frac{9}{7}\)

\(x=\frac{35}{14}-\frac{18}{14}\)

\(x=\frac{17}{14}\)

\(\frac{3}{4}.\frac{12}{7}+x=\frac{5}{2}\)

\(\frac{9}{7}+x=\frac{5}{2}\)

\(x=\frac{5}{2}-\frac{9}{7}\)

\(x=\frac{17}{14}\)

Vậy x = \(\frac{17}{14}\)

3,57 . x + 2,43 . x = 27 

x . ( 3 , 57 + 2 , 43 ) = 27 

x . 6 = 27 

x = \(\frac{9}{2}\)

Vạy x = \(\frac{9}{2}\)

14500 : 145  = 100

100 - 38 = 62

vậy x = 62

Phạm Ngọc Gia Hân  cảm ơn bạn 

=> x . ( 2 + 3 + 4 + 5 + 6 ) = x . 9 + 9999

=> x . 20 = x . 9 + 9999

=> x . 11 = 9999 ( cùng bớt x + 9 )

=> x = 9999 : 11

=> 909

  2x + 3x + 4x + 20x + 6x = 9x + 9999

           35x - 9x                = 9999

                 26x                 = 9999

                     x                 = 9999 / 26

Vậy : x = 9999 / 26

`75/20 - x = 3/2 xx 10`

`15/4 - x = 15`

              `x  = 15/4 - 15`

              `x  = -45/4`

`(12 xx 15) - X xx 1/4 = 120 xx 1/4`

 `180 - X xx 1/4    = 30`

            `X xx 1/4   = 180-30`

            `X xx 1/4   = 150` 

                     `X     = 150 : 1/4`

                     `X      = 600`

\(\dfrac{15}{4}-x=15\)

\(x=\dfrac{15}{4}-15\)

\(x=-\dfrac{45}{4}\)

\(\left(12\times15\right)-\dfrac{1}{4}x=120\times\dfrac{1}{4}\)

\(180-\dfrac{1}{4}x=30\)

\(-\dfrac{1}{4}x=30-180\)

\(-\dfrac{1}{4}x=-150\)

\(-x=-150:\dfrac{1}{4}\)

\(-x=-150\times4\)

\(-x=-600\)

\(x=600\)

1.53x201=10653

2.

a)4 xX-15x4=6x15+X

<=>4x-60=90+x

<=>4x-x=60+90

<=>3x=150

<=>x=50

b(102+28-2x):20-5=1

<=>(130-2x):20=6

<=>130-2x=120

<=>2x=10

<=>x=5

c)1999x-x=1999+1997+1999

<=>1998x=5995

<=>\(x\approx3\)

d)105-5x=150:15

<=>105-5x=10

<=>5x=95

<=>x=19

e)(x+1)+(x+2)+(x+3)+...+(x+6)=78

<=>6x+21=78

<=>6x=57

<=>x=9,5

1) 53x201=53x200+53=10600+53=10653

2a)

4x-15x4=6x15+x

4x-60=90+x

4x-x=90+60

3x=150

x=50

b) x=5

c) x=3

d)x=19

e) x=9,5