a: \(=\left\{\left[\left(20-\dfrac{1}{4}\right)\cdot0.2\right]+\dfrac{3}{20}\right\}\cdot5:\left[\left(2+\dfrac{25}{11}\cdot\dfrac{22}{100}\cdot10\right)\cdot\dfrac{1}{33}\right]\)

\(=\left\{\left[\dfrac{79}{20}+\dfrac{3}{20}\right]\right\}\cdot5:\left[\dfrac{356}{55}\cdot\dfrac{1}{33}\right]\)

\(=\dfrac{82}{20}\cdot5:\dfrac{3856}{1815}\simeq104,516\)

b: \(=\dfrac{13}{30}+\dfrac{28}{45}\cdot\dfrac{5}{2}\cdot\left[\dfrac{5}{6}:\dfrac{53}{90}\right]\cdot\dfrac{53}{50}\)

\(=\dfrac{13}{30}+\dfrac{14}{9}\cdot\dfrac{3}{2}=\dfrac{83}{30}\)

c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)

a.211,0465116

Sai thôi nha

{[(6,2:0,31-5/6.0,9).0,2+0,15]:0,2}:[(2+1/4/11.0,22:0,1).1/33]

={[(6,2:0,31-0,75).0,2+0,15]:0,2}:[(2+0,3:0,1).1/33]

={[19,25.0,2+0,15]:0,2}:[5.1/33]

={4:0,2}:5/33

=20:5/33

=132

\(\left(\dfrac{\left(6,2:0,31-\dfrac{5}{6}.0,9\right).\left(0,2+0,15\right):0,2}{\left(2+1\dfrac{4}{11}.0,22:0,1\right).\dfrac{1}{33}}\right)\)

\(=\dfrac{\left(20-0,75\right).0,35:0,2}{\left(2+3\right).\dfrac{1}{33}}\)

\(=\dfrac{19,25.0,35:0,2}{5.\dfrac{1}{33}}\)

\(=\dfrac{33,6875}{\dfrac{5}{33}}=\dfrac{1617}{80}=20,2125\)

( KT lại nha ! có thể mk tính chưa đúng )

cám ơn bn nhìu vì đã giúp mk 2 câu hỏi mk đang cần gấp(đây là câu 2)

a) \(\dfrac{3}{5}:\left(\dfrac{-1}{15}-\dfrac{1}{6}\right)+\dfrac{3}{5}:\left(\dfrac{-1}{3}-1\dfrac{1}{15}\right)\)

\(=\dfrac{3}{5}:\left(\dfrac{-1}{15}-1\dfrac{1}{15}-\dfrac{1}{6}+\dfrac{-2}{6}\right)\)

\(=\dfrac{3}{5}:\left(\dfrac{-17}{15}-\dfrac{1}{6}\right)\)

\(=\dfrac{3}{5}\cdot\dfrac{-10}{13}\)

\(=\dfrac{-6}{13}\)