\(a,\Rightarrow x=3\)

\(b,\Rightarrow2x-1=2\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\dfrac{3}{2}\)

\(c,\Rightarrow x-2=4\)

\(\Rightarrow x=6\)

\(d,\Rightarrow2x-3=3\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=3\)

a) x³ = 27 

x³ = 3³

x = 3

a)x³=3³

 ⇔x=3

\(a,\Rightarrow x=3\\ b,\Rightarrow2x-1=2\Rightarrow x=\dfrac{3}{2}\\ c,\Rightarrow\left[{}\begin{matrix}x-2=4\\x-2=-4\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\\ d,\Rightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\\ e,\Rightarrow2x+5=3^2=9\Rightarrow x=2\)

a) \(2^{4x+1}-8^{x+2}=0\)\(\Leftrightarrow2^{4x+1}-2^{3\left(x+2\right)}=0\)

\(\Leftrightarrow2^{4x+1}-2^{3x+6}=0\)\(\Leftrightarrow2^{4x+1}=2^{3x+6}\)

\(\Leftrightarrow4x+1=3x+6\)\(\Leftrightarrow4x-3x=6-1\)\(\Leftrightarrow x=5\)

Vậy \(x=5\)

b) \(3^2.9^{2x}=27^{x+3}\)\(\Leftrightarrow3^2.3^{2.2x}=3^{3\left(x+3\right)}\)\(\Leftrightarrow3^2.3^{4x}=3^{3x+9}\)

\(\Leftrightarrow3^{2+4x}=3^{3x+9}\)\(\Leftrightarrow2+4x=3x+9\)\(\Leftrightarrow4x-3x=9-2\)\(\Leftrightarrow x=7\)

Vậy \(x=7\)

c) \(8^{2x}.64^2=16^{x+4}\)\(\Leftrightarrow2^{3.2x}.2^{6.2}=2^{4\left(x+4\right)}\)\(\Leftrightarrow2^{6x}.2^{12}=2^{4\left(x+4\right)}\)

\(\Leftrightarrow2^{6x+12}=2^{4x+16}\)\(\Leftrightarrow6x+12=4x+16\)\(\Leftrightarrow6x-4x=16-12\)

\(\Leftrightarrow2x=4\)\(\Leftrightarrow x=2\)

Vậy \(x=2\)

Bài 1 :

a) 7^2x-1 = 343

=> 7^2x-1 = 7³

=> 2x - 1 = 3 => 2x = 4 => x = 2

b) (7x - 11)³ = 2⁵.3² + 200

=> (7x - 11)³ = 32.9 + 200

=> (7x - 11)³ = 488

xem kĩ lại đề này :vvv

c) 174 - (2x - 1)² = 5³

=> (2x - 1)² = 174 - 5³

=> (2x - 1)² = 174 - 125 = 49

=> (2x - 1)² = (\(\pm\)7)²

=> \(\orbr{\begin{cases}2x-1=7\\2x-1=-7\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=-3\end{cases}}\)

Mà x \(\in\)N nên x = 4( thỏa mãn điều kiện)

Bài 2 :

a) x⁵ = 32 => x⁵ = 2⁵ => x = 2

b) (x + 2)³ = 27

=> (x + 2)³ = 3³

=> x + 2 = 3 => x = 3 - 2 = 1

c) (x - 1)⁴ = 16

=> (x - 1)⁴ = 2⁴

=> x - 1 = 2 => x = 3 ( vì đề bài cho x thuộc N nên thỏa mãn)

d) (x - 1)⁸ = (x - 1)⁶

=> (x - 1)⁸ - (x - 1)⁶ = 0

=> (x - 1)⁶ [(x - 1)² - 1] = 0

=> \(\orbr{\begin{cases}\left(x-1\right)^6=0\\\left(x-1\right)^2-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\\left(x-1\right)^2=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\\left(x-1\right)^2=\left(\pm1\right)^2\end{cases}}\)

+) x - 1 = 1 => x = 2 ( tm)

+) x - 1 = -1 => x = 0 ( tm)

Vậy x = 1,x = 2,x = 0

\(a)\frac{5}{8}-x=2\frac{1}{6}\)

\(\Rightarrow\frac{5}{8}-x=\frac{13}{6}\)

\(\Rightarrow x=\frac{5}{8}-\frac{13}{6}\)

\(\Rightarrow x=\frac{15}{24}-\frac{52}{24}\)

\(\Rightarrow x=-\frac{37}{24}\)

\(b)\) \(\frac{4}{9}:x=-\frac{1}{3}+1\frac{1}{6}\)

\(\Rightarrow\frac{4}{9}:x=-\frac{1}{3}+\frac{7}{6}\)

\(\Rightarrow\frac{4}{9}:x=-\frac{2}{6}+\frac{7}{6}\)

\(\Rightarrow\frac{4}{9}:x=\frac{5}{6}\)

\(\Rightarrow x=\frac{4}{9}:\frac{5}{6}\)

\(\Rightarrow x=\frac{4}{9}.\frac{6}{5}\)

\(\Rightarrow x=\frac{8}{15}\)

\(c)\left(3x-2\right)^3=-\frac{1}{27}\)

\(\Rightarrow3x-2=-\frac{1}{3}\)

\(\Rightarrow3x=-\frac{1}{3}+2\)

\(\Rightarrow3x=-\frac{1}{3}+\frac{6}{3}\)

\(\Rightarrow3x=\frac{5}{3}\)

\(\Rightarrow x=\frac{5}{3}:3\)

\(\Rightarrow x=\frac{5}{9}\)

d ) và e ) tự làm 

Chúc bạn học tốt !!! 

Bài 1:

29.(85-47)+85.(47-29)

=29.38+85.18

=1102+1530

 =2632

BÀI 2

a, 15x = -75

        x =( -75) : 15

        x = -5

Vậy x= -5                                                            

b,-5x+8=-27

     -5x    = -27 - 8 

       -5x= -35

          x =-35 : -5

           x = 7

Vậy x = 7

c,3.(17 + x ) = - 42

       17 + x     = - 42 : 3

         17 + x    = -14

                x      = - 14 - 17

                 x = -31

Vậy x = - 31

d,-10 -( 2x -16) = 0

           2x - 16 = 10-0

           2x - 16 = 10

            2x = 10 +16

             2x = 26

                 x = 26 : 2

                  x = 13

 Vậy x = 13

e,( mik ko bít làm)

f,( tự làm nghen bạn)

x^3 = 27

x^3 = 3^3

=> x = 3

(2x-1)^3 = 8

(2x-1)^3 = 2^3

2x-1 = 2

2x = 2+1

2x = 3

x = 3:2

=> ko có x phù hợp.

(x-2)^2 = 16

(x-2)^2 = 4^2

x-2 = 4

x = 4+2

x = 6

Chúc bn học tốt!

x^3 = 27

x^3 = 3^3

Vậy x = 3

Đề bài 2 hình như sai bạn ạ

( x - 2 )^2 = 16

( x- 2 )^2 = 4^2

x - 2 = 4

x      = 4 + 2

x      = 6

Vậy x = 6

ta có: