a) `123 - 27 + 27 + 13 - 123`

`= (123 - 123) + (27 - 27) + 13`

`= 0 + 0 + 13`

`= 13`

`---`

b) `175 + 25 + 13 + 15 - 175 - 25`

`= (175-175)+(25-25)+25+13`

`=0+0+25+13`

`=28`

`---`

c) \(53\times39+47\times39+53\times21+47\times21\)

\(=\text{[}\left(53+47\right)\times39]+\left[\left(53+47\right)\times21\right]\)

\(=\left(100\times39\right)+\left(100\times21\right)\)

\(=3900+2100\)

`=6000`

`---`

d) \(49\times35+49\times16-49\times61\)

`=` \(49\times\left(35+16-61\right)\)

`=` \(49\times\left(-10\right)\)

`=-490`

a) 27-(-15)-2 =27+15-2

                     =40

b)(-12)+35-8=23-8

                    = 15

c)x + 37 + ( -17 ) + 25=x +20+25

                                   =x+45

d) ( -66 ) - ( y - 16 ) + 150=66-y+16 +150

                                          =66-y+166

                                          =66+166-y

                                          = 232+y

k mình nha!Chúc bạn học tốt!!!!^-^

a,27-(-15)-2

=42-2

=40

b,(-12)+35-8

=23-8

=15

c,x+37+(-17)+25

=x+[37+(-17)+25]

=x+45

d,(-66)-(y-16)+150

=(-66)-y+16+150

=-y+[(-66)+16+150]

=-y+100

=100+(-y)

=100-y

1) Ta có: \(3\left(x-1\right)-5\left(x-2\right)=4\left(x+1\right)\)

\(\Leftrightarrow3x-5-5x+10-4x-4=0\)

\(\Leftrightarrow-6x+1=0\)

\(\Leftrightarrow-6x=-1\)

hay \(x=\dfrac{1}{6}\)

2) Ta có: \(-2\left(x-2\right)-4\left(x+1\right)=-3\left(x+3\right)\)

\(\Leftrightarrow-2x+4-4x-4+3x+9=0\)

\(\Leftrightarrow-3x=-9\)

hay x=3

3) Ta có: \(3x^2+2x=0\)

\(\Leftrightarrow x\left(3x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-\dfrac{2}{3}\end{matrix}\right.\)

4) Ta có: \(x^2-5x=0\)

\(\Leftrightarrow x\left(x-5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)

5) Ta có: \(\left(2x-3\right)^2=36\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-3=6\\2x-3=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=9\\2x=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=-\dfrac{3}{2}\end{matrix}\right.\)

6) Ta có: \(\left(5x-1\right)^3=125\)

\(\Leftrightarrow5x-1=5\)

\(\Leftrightarrow5x=6\)

hay \(x=\dfrac{6}{5}\)

7) Ta có: \(3^{x+1}=27\)

\(\Leftrightarrow x+1=3\)

hay x=2

1: Ta có: \(2155-\left(174+2155\right)+\left(-68+174\right)\)

\(=2155-174-2155-68+174\)

=-68

2) Ta có: \(-25\cdot72+25\cdot21-49\cdot25\)

\(=-25\cdot\left(72-21+49\right)\)

\(=-25\cdot100=-2500\)

a) 22 + (2x -13) = 83 => 2x -13 = 61 => x = 37.

b) 51 - (-12 + 3x) = 27 => 63 - 3x = 27 => x = 12.

c) - (2x + 2) + 21 = - 23 => 2x + 2 = 44 => x = 21.

d) 25 - (25 - x) = 0 => 25 - 25 + x = 0 => x = 0.

a)\(x+\left(-5\right)=10\)

⇔\(x-5=10\)

⇔\(x=15\)

b)\(-2x-\left(-27\right)=25\)

⇔\(-2x+27=25\)

⇔\(-2x=-2\)

⇔\(x=1\)

a: \(\left(-10\right)\cdot35+10\cdot\left(-12\right)-\left(-10\right)\)

\(=\left(-10\right)\cdot35+\left(-10\right)\cdot12-\left(-10\right)\)

\(=-10\left(35+12-1\right)=-10\cdot46=-460\)

b: \(20\cdot\left(-345\right)+\left(-20\right)\cdot\left(-315\right)\)

\(=20\cdot\left(-345\right)+20\cdot315\)

\(=20\left(-345+315\right)=-30\cdot20=-600\)

c: \(25\left(27-55\right)-27\left(25-55\right)\)

\(=25\cdot27-25\cdot55-27\cdot25+27\cdot55\)

\(=27\cdot55-25\cdot55=2\cdot55=110\)

d: \(25\cdot\left(-415\right)+9\cdot\left(-15\right)\cdot418\)

\(=-25\cdot415-9\cdot15\cdot418\)

\(=-5\left(5\cdot415+3\cdot9\cdot418\right)\)

\(=-5\left(2075+11286\right)=-5\cdot13361=-66805\)

e: \(5+\left(-8\right)\cdot3\)

=5-24

=-19