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A. = 64.(4.9)+(32.2).137-(8.8).73
= 64.36+64.137-64.73
= 64.( 36+137-73)
= 64.100
= 6400
B. = 16.(3.13)+(2.8).150-(4.4).(62.3)
= 16.39+16.150-16.186
= 16.(39+150-186)
=16.3
= 48
C. =49.62+38.73+(31.2).51+(19.2).27
=49.62+38.73+62.51+38.27
= 62.(49+51)+38.(73+27)
= 62.100+38.100
=100.(62+38)
=100.100
=10000
\(\frac{-1997\cdot1996+1}{-1995\cdot\left(-1997\right)+1996}\)
\(=\frac{-1997\cdot\left(1995+1\right)+1}{1995\cdot1997+1996}\)
\(=\frac{-1997\cdot1995+\left(-1997\right)+1}{1995\cdot1997+1996}\)
\(=\frac{-1997\cdot1995+\left(-1996\right)}{1995\cdot1997+1996}\)
\(=-1\)
\(\frac{-1997.1996+1}{-1995.\left(-1997\right)+1996}\)
\(=\frac{-1997.1996+1}{1995.1997+1996}\)
\(=\frac{-1997.\left(1995+1\right)+1}{1995.1997+1996}\)
\(=\frac{-1997.1995+-1997+1}{1995.1997+1996}\)
\(=\frac{1995.-1997+-1996}{1995.1997+1996}\)
\(=\frac{-\left(1995.1997+1996\right)}{1995.1997+1996}\)
\(=-1\)
a)\(2.18.6+3.19.4+12.63\)
\(=2.6.18+3.4.19+12.63\)
\(=12.18+12.19+12.63\)
\(=12.\left(18+19+63\right)\)
\(=12.100\)
\(=1200\)
b)\(12.19+12.34+12.20+88.27\)
\(=12.19+12.34+12.20+22.4.3.9\)
\(=12.19+12.34+12.20+4.3.22.9\)
\(=12.19+12.34+12.20+12.198\)
\(=12.\left(19+34+20+198\right)\)
\(=12.271\)
\(=3252\)
c) \(28.17+66.14\)
\(=14.2.17+66.14\)
\(=14.34+66.14\)
\(=14.\left(34+66\right)\)
\(=14.100\)
\(=1400\)
a,2.18.6=216; 3.19.4=228;12.63= 756;216+228+756=1200 b,12.19=228;12.34=408;12.20=240;88.27=2376;228+408+240+2376=3252 c,1/1
a) 5x . 515 = 521
=> 5x = 521 : 515
=> 5x = 56
=> x = 6
a) 5x . 515 = 521
5x = 521 : 515
5x = 56
=> x = 6
b) 7x : 49 = 75
7x = 75 . 49
7x = 3675
(2.x-4). (x-1)=0
Số nào nhân với 0 cx bằng 0
TH1: 2.x-4=0. TH2: x-1=0
2x=0+4. x=0+1
2x=4. x=1
x=4÷2
x=2
\(\left(2x-4\right)\cdot\left(x-1\right)=0\Rightarrow\left(2x^2-6x+4\right)=0\Leftrightarrow\left(2x-4\right)\left(x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x-4=0\\x-1=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=1\end{cases}}\)
ủng hộ mik nha
\(36\div\left[7.\left(x-3\right)+4\right]=6\)
\(\Rightarrow7.\left(x-3\right)+4=36\div6\)
\(\Rightarrow7.\left(x-3\right)+4=6\)
\(\Rightarrow7.\left(x-3\right)=6-4\)
\(\Rightarrow7.\left(x-3\right)=2\)
\(\Rightarrow x-3=2\div7\)
\(\Rightarrow x-3=\frac{2}{7}\)
\(\Rightarrow x=\frac{2}{7}+3\)
\(\Rightarrow x=\frac{23}{7}\)
\(36:\left[7.\left(x-3\right)+4\right]=6\)
\(7.\left(x-3\right)+4=36:6\)
\(7.\left(x-3\right)+4=6\)
\(7.\left(x-3\right)=6-4\)
\(7.\left(x-3\right)=2\)
\(x-3=2:7\)
\(x-3=\frac{2}{7}\)
\(x=\frac{2}{7}+3\)
\(x=\frac{23}{7}\)
a) \(\left(x^2-9\right)\cdot\left(4^x-16\right)=0\)
\(\Rightarrow x^2-9=0\)hoặc \(4^x-16=0\)
\(x^2=9\) \(4^x=16\)
\(x^2=\left(\pm3\right)^2\) \(4^x=4^2\)
\(\Rightarrow x=\pm3\)hoặc \(x=2\)
b) \(5^x+5^{x+2}=650\)
\(\Rightarrow5^x+5^x\cdot25=650\)
\(\Rightarrow5^x\cdot\left(1+25\right)=650\)
\(\Rightarrow5^x\cdot26=650\)
\(\Rightarrow5^x=650\div26=25\)
\(\Rightarrow5^x=5^2\)
\(\Rightarrow x=2\)Vậy \(x=2\)
c) \(2^{x+2}-2^x=96\)
\(2^x\cdot4-2^x=96\)
\(2^x\cdot\left(4-1\right)=96\)
\(2^x\cdot3=96\)
\(2^x=96\div3=32\)
\(2^x=2^5\)Vậy \(x=5\)
a,38.37+38.73-110.29
= 38 . ( 37 + 73 ) -110.29
=38 . 110 - 110.29
= 110 . ( 38 - 29 )
= 110. 9
=990
k mình nha Nguyễn Hà My linh
38.37+38.73-110.29=38.(37+73)-110.29
=38.110-110.29
=110.(38-29)
=110.9
=990
Chúc học tốt nha!!!