<=> x² - 2x + 4x - 8 - 2 = 0

<=> x² + 2x - 10 = 0

<=> (x + 1)² = 11 => \(\orbr{\begin{cases}x+1=\sqrt{11}\\x+1=-\sqrt{11}\end{cases}\leftrightarrow\orbr{\begin{cases}x=\sqrt{11}-1\\x=-\sqrt{11}-1\end{cases}}}\)

Vậy ...

\(\Rightarrow x^2-2x+4x-8=2\)

\(\Rightarrow x^2-2x+4x=10\)

\(\Rightarrow x\left(x-2+4\right)=10\)

\(m=1+3+3^2+...+3^{100}\)

\(3m=3+3^2+...+3^{101}\)

\(\Rightarrow3m-m=3^{101}-1\)

\(\Leftrightarrow m=\frac{3^{101}-1}{2}\)

\(M=1+3+3^2+...+3^{100}\)

\(\Rightarrow\)\(3M=3+3^2+3^3+...+3^{101}\)

        \(-M=1+3+3^2+...+3^{100}\)

\(\Rightarrow\)\(2M=3^{101}-1\)

\(\Rightarrow M=\frac{3^{101}-1}{2}\)

a) pt => 2x-x=-25+5(chuyển vế đổi dấu) =>x=-20

b)pt=>\(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2x-1}-\frac{1}{2x+1}\)=\(\frac{2016}{2017}\)

      =>\(1-\frac{1}{2x+1}=\frac{2016}{2017}\)=>\(\frac{2x}{2x+1}=\frac{2016}{2017}\). Nhân chéo => x=1008

1-2+3-4+5-6+...+99-100+101 
= (1+3+5+...+101) - (2+4+6+...+100) 
tu 1 den 101 co : (101-1):2+1=51 
1+..+101 = (1+101)x 51:2= 2601 
tu 2 den 100 co : (100-2);2+1=50 
2+...+100 = (100 +2) x 50:2=2550 
=> A= 2601-2550=51

a) 2(x-3)-3(x-5)=4(3-x)-18

       2x-6-3x-15=12-4x-18

          2x-3x+4x=12-18+6+15

                     3x=15

                       x=15:3

                       x=5

Vậy x=5

Còn phần b đâu bạn?

TL

= (3⁹ (3 -1)) : 2⁹ : 3¹⁰ = 2 : 2⁹ x 1/3 = 1/2⁸ x 1/3

Khi nào rảnh vào kênh H-EDITOR xem vid nha!!! Thanks!