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\(ĐặtA=\frac{-5}{9.13}-\frac{7}{9.25}-\frac{13}{19.25}-\frac{31}{19.69}\)

\(\frac{-1}{2}.A=\frac{5}{13.18}+\frac{7}{18.25}+\frac{13}{25.38}+\frac{31}{38.69}\)

\(\frac{-1}{2}.A=\frac{1}{13}-\frac{1}{18}+\frac{1}{18}-\frac{1}{25}+\frac{1}{25}-\frac{1}{38}+\frac{1}{38}-\frac{1}{69}\)

\(\frac{-1}{2}.A=\frac{1}{13}-\frac{1}{69}\)

\(\frac{-1}{2}.A=\frac{56}{897}\)

\(A=\frac{56}{897}:\left(-\frac{1}{2}\right)\)

\(A=\frac{56}{897}.\left(-2\right)\)

\(A=\frac{-112}{897}\)

Đề của bn sai nên mk sửa lại

Ủng hộ mk nha ^_^

Đặt \(A=\frac{-5}{9.13}-\frac{7}{9.25}-\frac{-13}{19.25}-\frac{31}{19.69}\)

\(\frac{A}{2}=\frac{-5}{18.13}-\frac{7}{18.25}-\frac{-13}{38.25}-\frac{31}{38.69}\)

Đến đây tự làm

\(=\left[16\cdot\left(\dfrac{1}{13}-\dfrac{1}{20}+\dfrac{1}{20}-\dfrac{1}{27}+...+\dfrac{1}{62}-\dfrac{1}{69}\right)\right]:\dfrac{-112}{897}\)

\(=16\left(\dfrac{1}{13}-\dfrac{1}{69}\right)\cdot\dfrac{-897}{112}\)

\(=-\dfrac{897}{7}\cdot\dfrac{56}{897}=-8\)

mk thấy đề a có j  sai sai

= 112.[1 / 13.20 + 1 / 20.27 + ...... + 1 / 62.64]

= 112. [ 1/7 . ( 1/13 - 1/20 ) + 1/7 . ( 1/20 - 1/27 ) + ..... + 1/62.64 ]

= 112. [ 1/7. 1/13 - 1/7 - 1/20 + 1/7 . 20 - 1/7 . 1/27 + ..... + 1/ 62.64 ]

= 112. [ 1/7 . 1/13 + 1/ 62.64]