\(A=\frac{10-1\frac{1}{6}\times\frac{6}{7}}{21:\frac{11}{2}+5\frac{2}{11}}\)

\(A=\frac{10-\frac{7}{6}\times\frac{6}{7}}{21:\frac{11}{2}+\frac{57}{11}}\)

\(A=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}\)

\(A=\frac{9}{9}=1\)

_{^{NUGRUGJG T 0U3O UKWI FU JR HKLYG     QIQUTMVMNUCNREFDK4NMBNNCBRT 32C489898989  ROUH}} 

Bài làm

     \(\frac{10-1\frac{1}{6}\times\frac{6}{7}}{21:\frac{11}{2}+5\frac{2}{12}}\)

\(=\frac{10-\frac{7}{6}\times\frac{6}{7}}{21\times\frac{2}{11}+\frac{62}{12}}\)

\(=\frac{10-1}{\frac{42}{11}+\frac{62}{12}}\)

\(=9:(\frac{42}{11}+\frac{62}{12})\)

\(=9:\left(\frac{504}{132}+\frac{682}{132}\right)\)

\(=9:\frac{1186}{132}\)

\(=9:\frac{593}{66}\)

\(=9\times\frac{66}{593}\)

\(=\frac{594}{593}\)

# Hông bt có đúng k nx. #
 

\(\frac{6\div\frac{3}{5}-1\frac{1}{6}\times\frac{6}{7}}{4\frac{1}{5}\times\frac{10}{11}+5\frac{2}{11}}=\frac{6\div\frac{3}{5}-\frac{1\times6+1}{6}\times\frac{6}{7}}{\frac{4\times5+1}{5}\times\frac{10}{11}+\frac{5\times11+2}{11}}\)

\(=\frac{6\div\frac{3}{5}-\frac{7}{6}\times\frac{6}{7}}{\frac{21}{5}\times\frac{10}{11}+\frac{57}{11}}=\frac{\left(6\div\frac{3}{5}\right)-\left(\frac{7}{6}\times\frac{6}{7}\right)}{\left(\frac{21}{5}\times\frac{10}{11}\right)+\frac{57}{11}}\)

\(=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}=\frac{9}{\frac{99}{11}}=\frac{9}{9}=1\)

a= (\(\frac{2}{5}\)+\(\frac{2}{9}\)+\(\frac{2}{11}\)\(\times\)\(\frac{5}{7}\)\(+\frac{7}{9}\)\(+\frac{7}{11}\)\()\)

a) \(A=10-1\frac{1}{6}.\frac{6}{7}\)

\(=10-\frac{7}{6}.\frac{6}{7}\)

\(=10-1=9\)

b) \(B=21:\frac{11}{2}+5\frac{2}{11}\)

\(=\frac{42}{11}+\frac{57}{11}=9\)

c) \(A=9;B=9\)

\(A.B=9.9=81\)

d) \(A=9;B=9\)

\(A:B=9:9=1\)

a) A = \(10-1\frac{1}{6}\times\frac{6}{7}\)= \(10-\frac{7}{6}\times\frac{6}{7}\)= 10 - 1 = 9

b) B = \(21:\frac{11}{2}+5\frac{2}{11}\)= \(\frac{42}{11}+\frac{57}{11}\)= 9

c) A x B = 9 x 9 = 81

c) A : B = 9 : 9 = 1

\(=\frac{6\times\frac{5}{3}-\frac{7}{6}\times\frac{6}{7}}{\frac{21}{5}\times\frac{10}{11}+\frac{57}{11}}=\frac{10-1}{\frac{42}{11}+\frac{57}{11}}=\frac{9}{\frac{99}{11}}\)=1