\(\dfrac{637\times527-189}{526\times637+448}\)

\(=\dfrac{637\times\left(526+1\right)-189}{526\times637+448}\)

\(=\dfrac{637\times526+637-189}{526\times637+448}\)

\(=\dfrac{637\times526+448}{526\times637+448}\)

\(=\dfrac{1}{1}\)

\(=1\)

\(\dfrac{\left(637\cdot527-189\right)}{\left(526\cdot637+448\right)}\)

\(=\dfrac{\left(637\cdot526+637-189\right)}{\left(526\cdot637+448\right)}\)

\(=\dfrac{637\cdot526+448}{637\cdot526+448}=1\)

\(=\dfrac{637.\left(526+1\right)-189}{526.637+448}=\dfrac{637.526+637-189}{526.637+446}=\dfrac{637.526+448}{526.637+448}=1\)

\(\left(637.527-189\right):\left(526.637+448\right)\)

\(=\left(335699-189\right):\left(335062+448\right)\)

\(=335510:335510\)

\(=1\)

Bạn tham khảo lời giải:

a) (1 989. 1 990 + 3 978): (1 992. 1 991 – 3 984)

+) 1 989. 1 990 + 3 978 = 1 989. 1 990 + 1 989. 2 = 1 989. (1 990 + 2) = 1 989. 1 992

+) 1 992. 1 991 – 3 984 = 1 992. 1 991 – 1 992. 2 = 1 992. (1 991 – 2) = 1 992. 1 989

Do đó: 

(1 989. 1 990 + 3 978): (1 992. 1 991 – 3 984)

= (1 989. 1 992): (1 992. 1 989)

= (1 989: 1 989). (1 992: 1 992)

= 1. 1  

= 1

b) (637. 527 – 189): (526. 637 + 448)

+) 637. 527 – 189 = 637. (526 + 1) – 189 = 637. 526 + 637. 1 – 189 

= 637. 526 + (637 – 189) = 637. 526 + 448

Do đó: (637. 527 – 189): (526. 637 + 448) = (637. 526 + 448): (637. 526 + 448) = 1.

\(a)\)\(\left(1989.1990+3978\right)\div\left(1992.1991-3984\right)\)

\(=\)\(\left(1989.1990+1989.2\right)\div\left(1992.1991-1992.2\right)\)

\(=\)\(\left[1989.\left(1990+2\right)\right]\div\left[1992.\left(1991-2\right)\right]\)

\(=\)\(\left(1989.1991\right)\div\left(1992.1989\right)\)

\(=\)\(1\)

\(b)\)\(\left(637.527-189\right)\div\left(526.637+448\right)\)

\(=\)\(\left[637.\left(526-1\right)-189\right]\div\left(526.637-448\right)\)

\(=\)\(\left[637.526+\left(637-198\right)\right]\div\left(637.526-448\right)\)

\(=\)\(\left(636.526+448\right)\div\left(637.526-448\right)\)

\(=\)\(1\)

a ) 17 x 4 = ( 15 + 2 ) x 4 = 15 x 4 + 2 x 4 = 60 + 8 = 68

      25 x 28 = 25 x ( 20 + 8 ) = 25 x 20 + 25 x 8 = 500 + 200 = 700

b ) 13 x 12 = 13 x ( 10 + 2 ) = 13 x 10 + 13 x 2 = 130 + 26 = 156

      53 x 11 = 53 x ( 10 + 1 ) = 53 x 10 + 53 x 1 = 530 + 53 = 583

      39 x 101 = 39 x ( 100 + 1 ) = 39 x 100 + 39 x 1 = 3900 + 39 = 3939

a) Ta có:

\(17\times4=\left(15+2\right)\times4=15\times4+2\times4=60+8=68\)

\(25\times28=25\times\left(20+8\right)=25\times20+25\times8=500+200=700\)

b) Ta có:

\(13\times12=13\times\left(10+2\right)=13\times10+13\times2=130+26=156\)

\(53\times11=53\times\left(10+1\right)=53\times10+53\times1=530+53=583\)

\(39\times101=39\times\left(100+1\right)=39\times100+39\times1=3900+39=3939\)

Lời giải:

a. $=128-78+100-128=(128-128)+100-78=0+100-78=22$

b. $=125-100+93-218= (125+93-218)-100=0-100=-100$

c. $=453+74-79-527$

$=(453+74-527)-79 =0-79=-79$
d.

$=-825+775+825=(825-825)+775=0+775=775$

e.

$=163-413-187+637 = (163+637)-(413+187) = 800-600=200$