= \(\frac{11}{2}\)- \(\frac{101}{7}\): \(\frac{9}{13}\)- \(\frac{25}{7}\): \(\frac{9}{13}\)

= \(\frac{-41}{2}\)

(chỉ cần sử dụng máy tính cầm tay là có thể giải được)

hãy tìm ba phân số lớn hơn \(\frac{1}{3}\)và nhỏ hơn\(\frac{1}{2}\)sau đó hãy tính tổng ba phân số vừa tìm được ở trên.

\(\left(1+2\frac{1}{4}-3\frac{1}{3}\right):\left(1+3\frac{1}{2}-4\frac{7}{12}\right)\)

\(=\left(1+2-3+\frac{1}{4}-\frac{1}{3}\right):\left(1+3-4+\frac{1}{2}-\frac{7}{12}\right)\)

\(=\frac{-1}{12}:\frac{-1}{12}=\frac{-1}{12}.\frac{12}{-1}=\frac{12}{12}=1\)

a. (1 + \(2\frac{1}{4}\) -  \(3\frac{1}{3}\)) : (1 + \(3\frac{1}{2}\) - \(4\frac{7}{12}\))

= \(-\frac{1}{12}\): ( \(-\frac{1}{12}\))

= 1

b. \(5\frac{1}{2}\)-  \(14\frac{3}{7}\) :  \(\frac{9}{13}\)-  \(3\frac{4}{7}\) :  \(\frac{9}{13}\)

= \(\frac{11}{2}\)+ (\(14\frac{3}{7}-3\frac{4}{7}\)) : \(\frac{9}{13}\)

= \(\frac{11}{2}\)- 26

= \(-\frac{41}{2}\)

1. \(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)

= \(\frac{5}{9}\) .(\(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\) )

= \(\frac{5}{9}\) . 1 = \(\frac{5}{9}\)

Giúp Mik ik mai nộp oy

\(a,\frac{7}{12}\cdot\frac{6}{11}+\frac{7}{12}\cdot\frac{5}{11}+2\frac{7}{12}\)

\(=\frac{7}{12}\cdot\left(\frac{6}{11}+\frac{5}{11}\right)+2\frac{7}{12}\)

\(=\frac{7}{12}+\frac{31}{12}\)

\(=\frac{38}{12}=\frac{19}{6}\)

\(b,\frac{-5}{9}\cdot\frac{-6}{13}+\frac{5}{-9}\cdot\frac{-5}{13}-\frac{5}{9}\)

\(=\frac{-5}{9}\cdot\frac{-6}{13}+\frac{-5}{9}\cdot\frac{-5}{13}+\frac{-5}{9}\cdot1\)

\(=\frac{-5}{9}\cdot\left(\frac{-6}{13}+\frac{-5}{13}+1\right)\)

\(=\frac{-5}{9}\cdot\left(\frac{-11}{13}+1\right)\)

\(=\frac{-5}{9}\cdot\frac{2}{13}\)

\(=\frac{-10}{117}\)

\(c,\)\(0,8\cdot\frac{-15}{14}-\frac{4}{5}\cdot\frac{13}{14}-1\frac{2}{5}\)

\(=\frac{4}{5}\cdot\frac{-15}{14}-\frac{4}{5}\cdot\frac{13}{14}-\frac{7}{5}\)

\(=\frac{4}{5}\cdot\left(\frac{-15}{14}-\frac{13}{14}\right)-\frac{7}{5}\)

\(=\frac{4}{5}\cdot\left(-2\right)-\frac{7}{5}\)

\(=\frac{-8}{5}-\frac{7}{5}\)

\(=-3\)

\(d,\)\(75\%\cdot\frac{6}{7}+5\%\cdot\frac{6}{7}+\frac{7}{10}\cdot1\frac{1}{7}\)

\(=\frac{3}{4}\cdot\frac{6}{7}+\frac{1}{20}\cdot\frac{6}{7}+\frac{7}{10}\cdot\frac{8}{7}\)

\(=\left(\frac{3}{4}+\frac{1}{20}\right)\cdot\frac{6}{7}+\frac{7}{10}\cdot\frac{8}{7}\)

\(=\frac{4}{5}\cdot\frac{6}{7}+\frac{4}{5}\cdot1\)

\(=\frac{4}{5}\cdot\left(\frac{6}{7}+1\right)\)

\(=\frac{4}{5}\cdot\frac{13}{7}\)

\(=\frac{52}{35}\)

a)7/12.6/11+7/12.5/11-2.7/12

=7/12(6/11+5/11-2)

=7/12(1-2)

=7/12.(-1)

=-7/12