575 - (6y+70) = 445

=> 6y + 70 = 575 - 445 = 130

=> 6y = 130- 70 = 60

=> y = 60 : 6 = 10

=> y = 10

\(575-\left(6y+70\right)=445\)

\(\Rightarrow6y+70=575-445\)

\(\Rightarrow6y+70=130\)

\(\Rightarrow6y=130-70\)

\(\Rightarrow6y=60\)

\(\Rightarrow y=60:6\)

\(\Rightarrow y=10\)

bằng 83/90

\(\frac{1}{2}+\frac{1}{5}+\frac{2}{9}\)

=\(\frac{45}{90}+\frac{18}{90}+\frac{20}{90}\)

=\(\frac{83}{90}\)

Suy ra 24×25=-4(7x-3)

Suy ra 600=-28x+12

Suy ra -28x=600-12=588

Suy ra x=588/-28=-21

\(\frac{-3}{-9}\)+\(\frac{8}{7}\)+\(\frac{1}{-3}\)+\(\frac{26}{14}\)

=+\(\frac{8}{7}\)+\(\frac{1}{-3}\)+\(\frac{13}{7}\)

=\(\frac{1}{3}\)+\(\frac{1}{-3}\)+\(\frac{8}{7}\)+\(\frac{13}{7}\)

=0+\(\frac{8}{7}\)+\(\frac{13}{7}\)

=\(\frac{21}{7}\)

=3

Mình đang rất cần.

A={0;1;2;3;4;5;6;7;8} - cách 1

A={X {kí hiệu thuộc} N/X<9}- cách 2 

k nha

A={0;1;2;3;4;5;6;7;8;9}

A={\(n\in Nln< 9\)}

(x + 3)(y - 1) = 4

=> x + 3 và y - 1 thuộc Ư(4)

ta có bảng :

(x + 3) . (y - 1) = 4 

Ta có bảng sau:

Vậy....

(xl mình kẻ thừa 2 cột)

a, 2^(x+1)+2^x=192

=>2^x . 2+2^x=192

=>2^x(2+1)=192

=>2^x=64

=>x=6

Vây x=6

b,2^x . (2^2)^2=(2^3)^2

=>2^x . 4^2=8^2

=>2^x . 16=64

=>2^x=4

=>x=2

Vậy x=2

2^x +2^4=2^6

2^x=2^2

x=2