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Bài làm:
a) \(\frac{x}{3}=\frac{2}{3}+\left(-\frac{1}{7}\right)\)
<=>\(\frac{x}{3}=\frac{2.7-1.3}{3.7}\)
<=>\(\frac{x}{3}=\frac{11}{21}\)
<=> \(21.x=33\)
<=> \(x=\frac{11}{7}\)
b) \(x-\frac{1}{4}=\frac{2}{13}\)
<=> \(x=\frac{1}{4}+\frac{2}{13}\)
<=> \(x=\frac{13.1+2.4}{4.13}\)
<=> \(x=\frac{21}{52}\)
c)\(\frac{4}{7}.x=\frac{9}{8}-\frac{125}{1000}\)
<=> \(\frac{4}{7}.x=\frac{9}{8}-\frac{1}{8}\)
<=> \(\frac{4}{7}.x=\frac{8}{8}\)
<=> \(x=1:\frac{4}{7}\)
<=> \(x=\frac{7}{4}\)
Học tốt!!!!
7 + 67 + 56 - 76 + 368 - 93 + 45 -88 =
=? ? ? ? ? ? ?
= ? ? ? ? ?
= ?
Bài 1
a) (3x - 2⁴).7³ = 2.7⁴
3x - 16 = 2.7⁴ : 7³
3x - 16 = 2.7
3x - 16 = 14
3x = 14 + 16
3x =30
x = 30 : 3
x = 10
b) x - [42 + (-28)] = -8
x - 14 = -8
x = -8 + 14
x = 6
c) 4 - 7.x = x - (13 - 4)
x + 7x = 4 + 9
8x = 13
x = 13/8
Bài 1: a, (3\(x\) - 24 ).73 = 2.74
3\(x\) - 24 = 2.74 : 73
3\(x\) - 16 = 14
3\(x\) = 30
\(x\) = 10
b, \(x\) - (42 + (-28) ] = -8
\(x\) - 14 = -8
\(x\) = 14 - 8
\(x\) = 6
c, 4 - (7\(x\)) = \(x\) - (13 - 4)
4 - 7\(x\) = \(x\) - 9
\(x\) + 7\(x\) = 4 + 9
8\(x\) = 13
\(x\) = \(\dfrac{13}{8}\)
\(a,\dfrac{2}{3}.x=\dfrac{2}{7}\\ x=\dfrac{2}{7}:\dfrac{2}{3}=\dfrac{3}{7}\\ ---\\ b,x.\dfrac{3}{5}=\dfrac{2}{5}\\ x=\dfrac{2}{5}:\dfrac{3}{5}=\dfrac{2}{3}\\ ---\\ c,x:\dfrac{8}{13}=\dfrac{13}{7}\\x=\dfrac{13}{7}.\dfrac{8}{13}=\dfrac{8}{7}\\ ----\\ d,\dfrac{3}{2}:x=\dfrac{7}{4}\\ x=\dfrac{3}{2}:\dfrac{7}{4}=\dfrac{3}{2}.\dfrac{4}{7}=\dfrac{6}{7}\)
a: \(=\dfrac{-3}{5}\cdot\dfrac{5}{7}+\dfrac{-3}{5}\cdot\dfrac{3}{7}+\dfrac{-3}{5}\cdot\dfrac{6}{7}\)
\(=\dfrac{-3}{5}\left(\dfrac{5}{7}+\dfrac{3}{7}+\dfrac{6}{7}\right)=\dfrac{-3}{5}\cdot2=-\dfrac{6}{5}\)
b: \(=\dfrac{3}{13}\cdot\dfrac{6}{11}+\dfrac{3}{13}\cdot\dfrac{5}{11}-\dfrac{2}{13}=\dfrac{3}{13}-\dfrac{2}{13}=\dfrac{1}{13}\)
c: =>1/2x+1+3/8=7/16
=>1/2x=-15/16
=>x=-15/8
d: =>5/2x-1/3=1/6*(-9)/2=-9/12=-3/4
=>5/2x=-3/4+1/3=-9/12+4/12=-5/12
=>x=-1/6
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
Bài 1: Tìm \(x\)
a; \(x-2\) + 7 = 1.3.(-9)
\(x\) - 2 + 7 = 3.(-9)
\(x\) - 2 + 7 = - 27
\(x\) = - 27 - 7 + 2
\(x\) = - 34 + 2
\(x\) = - 32
Vậy \(x=-32\)
Bài 1
c; - 2\(x\) + 5 = 7
- 2\(x\) = 7 - 5
- 2\(x\) = - 2
\(x\) = -2 : (-2)
\(x\) = - 1
Vậy \(x\) = - 1
Bai 2 :
\(\hept{\begin{cases}x+y=7\\x-7=13\end{cases}\Leftrightarrow\hept{\begin{cases}x+y=7\\x=20\end{cases}}}\)
Thay x vào phương trình đầu ta có :
\(20+y=7\Leftrightarrow y=-13\)
Vậy \(\left\{x;y\right\}=\left\{20;-13\right\}\)
Thử \(20-13=7\); \(20-7=13\)( thỏa mãn )
a) x=3/7
b)x=8/7
c)x=6/7
a)\(x=\dfrac{2}{7}:\dfrac{2}{3}=\dfrac{3}{7}\)
b)\(x=\dfrac{13}{7}\times\dfrac{8}{13}=\dfrac{8}{7}\)
c)\(x=\dfrac{3}{2}:\dfrac{7}{4}=\dfrac{6}{7}\)