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\(6\times\left(y+9845\right)=29042\times6\)
\(y+9845\) \(=29042\times6\div6\)
\(y+9845\) \(=29042\)
\(y\) \(=29042-9845\)
\(y\) \(=19197\)
\(\left(x\div3\right)\times8=8\times3198\)
\(x\div3\) \(=8\times3198\div8\)
\(x\div3\) \(=3198\)
\(x\) \(=3198\times3\)
\(x\) \(=9594\)
\(6.\left(x+9845\right)=29042.6\)
\(x+9845=29042\)
\(x=19197\)
\(\left(x:3\right).8=8.3198\)
\(x:3=3198\)
\(x=1066\)
a) 6*(x+ 9845) = 29042*6
6*(x + 9845) = 174252
x + 9845 = 174252
x = 174252 - 9845
x = 164407
b) (x:3)*8= 8 * 3198
x:3 *8= 25584
x:3 = 25584:8
x:3 = 3198
x = 3198*3
x = 9594
a,
6.(x+9845)=29042.6
x+9845=29042
x=29042-9845
x=19197
b,
(x:3).8=8.3198
x:3=3198
x=3198.3
x=9594
câu 9
6x(y + 9845)=174252
(y + 9845)=174252:6
(y + 9845)=29042
y=29042-9845
y=19197
Vậy y=19197
câu 9: 6.(y+9845)=29042.6
=>6.(y+9845)=174252
=>y+9845=174252:6
=>y+9845=29042
=>y=29042-9845
=>y=19197
Vậy y=19197
1. A) 225886 + 779 × 8
= 225886 + 6232
= 232118
B) 125 × 5 × 20 × 8
= (125 × 8) × (5 × 20)
= 1000 × 100
= 100000
C) 47286 : 2 + 14765
= 23643 + 14765
= 38408
D) 91428 - 23560 : 5
= 91428 - 4712
= 86716
3. A) 36 × 532 + 63 × 532 + 532
= 532 × (36 + 63 + 1)
= 532 × 100
= 53200
B) 679 × 123 + 679 - 679 × 24
= 679 × (123 + 1 - 24)
= 679 × 100
= 67900
C) 245 × 327 - 245 × 18 - 9 × 245
= 246 × (327 - 18 - 9)
= 245 × 300
= 73500
3. Tính bằng cách thuận tiện nhất
A, 36 x 532 + 63 x 532 + 532
= (36 + 63 + 1) x 532 = 100 x 532 = 53 200
B, 679 x 123 + 679 - 679 x 24
= 679 x (123 + 1 - 24)
= 679 x 100 = 67 900
C, 245 x 327 - 245 x 18 - 9 x 245
= 245 x (327 - 18 - 9)
= 245 x 300
= 73 500
Bài 2:
a: \(6\cdot\left(x+9845\right)=29042\)
=>\(x+9845=\dfrac{29042}{6}=\dfrac{14521}{3}\)
=>\(x=\dfrac{14521}{3}-9845=-\dfrac{15014}{3}\)
b: \(\left(x:3\right)\cdot8=8\cdot3198\)
=>\(x:3=3198\)
=>\(x=3198\cdot3=9594\)
Bài 1:
a: \(225886+779\cdot8\)
\(=225886+6232\)
\(=232118\)
b: \(125\cdot5\cdot20\cdot8\)
\(=\left(125\cdot8\right)\cdot\left(5\cdot20\right)\)
\(=1000\cdot100=100000\)
c: \(47286:2+14765\)
\(=23643+14765\)
=38408
d: \(91428-23560:5\)
\(=91428-4712\)
=86716
Lời giải đầy đủ:
Bài 3:tìm x
A,
6.(x+9845)=29042.6
(x+9845)=29042.6:6
x+9845=29042
x=29042-9845
x=19197.
B,
(x:3).8=8.3198
(x:3)=3198.8:8
x:3=3198
x=3198.3
x=9594.
Bài 7:
A/191+x+9=43.5
200+x=215
x=215-200
x=15.
B/x.25.4=125.8
x.100=1000
x=1000:100
x=10.
Bài 8:
A/ 128.x-12.x-16.x=5208000
(128-12-16).x=5208000
100.x=5208000
x=5208000:100
x=52080.
B/ x.27+x.30+x.43=210500
x.(27+30+43)=210500
x.100=210500
x=210500:100
x=2105.
K mình nhé!
\(a,\dfrac{4}{5}+\dfrac{2}{7}=\dfrac{28}{35}+\dfrac{10}{35}=\dfrac{38}{35}.\)
\(b,2-\dfrac{8}{9}=\dfrac{18}{9}-\dfrac{8}{9}=\dfrac{10}{9}.\)
\(c,\dfrac{5}{8}\times3=\dfrac{5\times3}{8}=\dfrac{15}{8}.\)
\(d,5:\dfrac{6}{21}=5\times\dfrac{21}{6}=\dfrac{5\times21}{6}=\dfrac{105}{6}=\dfrac{35}{2}.\)
\(đ,\dfrac{3}{5}\times\dfrac{4}{5}\times\dfrac{6}{7}=\dfrac{3\times4\times6}{5\times5\times7}=\dfrac{72}{175}.\)
\(a,\dfrac{4}{5}+\dfrac{2}{7}=\dfrac{28}{35}+\dfrac{10}{35}=\dfrac{38}{35}\)
\(b,2-\dfrac{8}{9}=\dfrac{18}{9}-\dfrac{8}{9}=\dfrac{10}{9}\)
\(c,\dfrac{5}{8}\times3=\dfrac{5\times3}{8\times1}=\dfrac{15}{8}\)
\(d,\dfrac{3}{5}\times\dfrac{4}{5}\times\dfrac{6}{7}=\dfrac{3\times4\times6}{5\times5\times7}=\dfrac{72}{175}\)