Bài 1

a/ $\frac{-3}{7}-\left(\frac{2}{3}-\frac{3}{7}\right)$

$\backslash (=\backslash frac\{-3\}\{7\}-\backslash frac\{2\}\{3\}+\backslash frac\{3\}\{7\}\backslash )$

\(=\left(\frac{-3}{7}+\frac{3}{7}\right)-\frac{2}{3}\)

\(=0-\frac{2}{3}\)

\(=\frac{-2}{3}\)

a) \(\frac{-3}{7}-\left(\frac{2}{3}-\frac{3}{7}\right)\)

\(=\frac{-3}{7}-\frac{2}{3}+\frac{3}{7}\)

\(=\left(\frac{3}{7}-\frac{3}{7}\right)-\frac{2}{3}\)

\(=0-\frac{2}{3}\)

\(=-\frac{2}{3}\)

b) \(\frac{2}{15}\div\left(\frac{1}{3}.\frac{4}{5}-\frac{1}{3}.\frac{6}{5}\right)\)

\(=\frac{2}{15}\div\left[\frac{1}{3}\left(\frac{4}{5}-\frac{6}{5}\right)\right]\)

\(=\frac{2}{15}\div\left[\frac{1}{3}.\frac{-2}{5}\right]\)

\(=\frac{2}{15}\div\frac{-2}{15}\)

\(=\frac{2}{15}\times\frac{15}{-2}\)

\(=\frac{2}{-2}=-1\)

\(\frac{3}{4}+\frac{1}{4}x=\frac{5}{8}\)

\(\Leftrightarrow\frac{1}{4}x=\frac{5}{8}-\frac{3}{4}\)

\(\Leftrightarrow\frac{1}{4}x=\frac{5}{8}-\frac{6}{8}\)

\(\Leftrightarrow\frac{1}{4}x=\frac{-1}{8}\)

\(\Leftrightarrow x=\frac{-1}{8}\div\frac{1}{4}\)

\(\Leftrightarrow x=\frac{-1}{8}\times\frac{4}{1}\)

​\(\Leftrightarrow x=\frac{-4}{8}\)​

\(\Leftrightarrow x=\frac{-1}{2}\)

\(2.THPT\)

\(A=\frac{9}{1.2}+\frac{9}{2.3}+\frac{9}{3.4}+...+\frac{9}{98.99}+\frac{9}{99.100}\)

\(A=9\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\right)\)

\(A=9\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\right)\)

\(A=9\left(1-\frac{1}{100}\right)\)

\(A=9.\frac{99}{100}\)

\(A=\frac{891}{100}\)

\(B=\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{93.95}\)

\(B=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{93}-\frac{1}{95}\)

\(B=\frac{1}{5}-\frac{1}{95}\)

\(B=\frac{18}{95}\)

\(D=\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\)

\(D=\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\)

\(D=\frac{1}{2}-\frac{1}{28}\)

\(D=\frac{13}{28}\)

a, Câu hỏi của Nguyễn Ánh Ngân - Toán lớp 6 - Học toán với OnlineMath

b, Câu hỏi của Vũ Xuân Hiếu - Toán lớp 6 | Học trực tuyến

c)$x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-\frac{1}{20}-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}=\frac{5}{24}$