a: \(1\dfrac{3}{4}=1+\dfrac{3}{4}\)

b: \(3\dfrac{5}{9}=3+\dfrac{5}{9}\)

c: \(1\dfrac{9}{10}=1+\dfrac{9}{10}\)

d: \(3\dfrac{25}{20}=3+\dfrac{5}{4}\)

e: \(=2\dfrac{55}{30}=2+\dfrac{11}{6}\)

Lời giải:
a.

$x=\frac{7}{25}+\frac{-1}{5}=\frac{7}{25}+\frac{-5}{25}=\frac{7-5}{25}=\frac{2}{25}$

b.

$x=\frac{5}{11}+\frac{4}{-9}=\frac{5}{11}-\frac{4}{9}=\frac{45}{99}-\frac{44}{99}=\frac{1}{99}$

c.

$\frac{x}{-1}=\frac{-1}{3}-\frac{5}{9}=\frac{-3}{9}-\frac{5}{9}=\frac{-8}{9}$

$x=(-1).\frac{-8}{9}=\frac{8}{9}$

tìm x biết:

(3x-1) [- 1/2x+5]=0

1/4+1/3:(2x-1)=-5

[2x+3/5]² - 9/25=0

-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6

[x+1/2]x [2/3-2x]=0

17/2-|2x-3/4|=-7/4

2/3x-1/2x =5/12

(x+1/5)²+17/25=26/25

[x.44/7+3/7].11/5-3/7=-2

3[3x-1/2]+1/9=0

Toán lớp 6Tìm x

 Trả lời  Câu hỏi tương tự

Chưa có ai trả lời câu hỏi này,bạn hãy là người đâu tiên giúp nguyenvanhoang giải bài toán này !

3(3x-1/2)^3+1/9=0

a) 3/7 + 4/9 + 4/7 + 5/9

= ( 3/7 + 4/7 ) + ( 4/9 + 5/9 )

= 7/7 + 9/9

= 1  + 1 

= 2

b)1/5 + 4/10 + 9/15 + 16/20 + 25/25 + 36/30 + 49/35 + 64/40 + 81/45

= 1/5 + 2/5 + 3/5 + 4/5 + 5/5 + 6/5 + 7/5 + 8/5 + 9/5

= ( 1/5 + 9/5 ) + ( 2/5 + 8/5 ) + (7/5 + 3/5 ) + ( 4/5 + 6/5  ) + 5/5

= 2 + 2 + 2 + 2 + 1

= 2  x 4 + 1

= 8  +1 

= 9

c)  1/8 + 1/12 + 3/8 + 5/12

= ( 1/8 + 3/8 ) + ( 1/12 + 5/12)

= 4/8 + 6/12

= 1/2 + 1/2

= 2/4 = 1/2

mỏi tay rồi

d; (1 - \(\dfrac{1}{2}\)) x (1 - \(\dfrac{1}{3}\)) x (1 - \(\dfrac{1}{4}\)) x ... x ( 1 - \(\dfrac{1}{100}\))

 = \(\dfrac{1}{2}\) x \(\dfrac{2}{3}\)  x \(\dfrac{3}{4}\) x \(\dfrac{3}{4}\) x ... x \(\dfrac{99}{100}\)

= \(\dfrac{1}{100}\)

a) x=7

b)x=2/3

c)x=-13

d)x=3

e)x=-1

a) \(x=\frac{7}{25}+\frac{-1}{5}\)

\(\Rightarrow x=\frac{2}{25}\)

Vậy \(x=\frac{2}{25}\)

b) \(x=\frac{5}{11}+\frac{4}{-9}\)

\(\Rightarrow x=\frac{1}{99}\)

Vậy \(x=\frac{1}{99}\)

c) \(\frac{5}{9}+x=\frac{-1}{3}\)

\(\Rightarrow x=\frac{-1}{3}-\frac{5}{9}\)

\(\Rightarrow x=\frac{-8}{9}\)

Vậy \(x=\frac{-8}{9}\)

d) \(\frac{3}{4}-x=-1\)

\(\Rightarrow x=\frac{3}{4}-\left(-1\right)\)

\(\Rightarrow x=\frac{7}{4}\)

Vậy \(x=\frac{7}{4}\)

e) \(x+4=\frac{1}{5}\)

\(\Rightarrow x=\frac{1}{5}-4\)

\(\Rightarrow x=\frac{-19}{5}\)

Vậy \(x=\frac{-19}{5}\)

f) \(x-\frac{1}{5}=2\)

\(\Rightarrow x=2+\frac{1}{5}\)

\(\Rightarrow x=\frac{11}{5}\)

Vậy \(x=\frac{11}{5}\)

g) \(x+\frac{5}{3}=\frac{1}{81}\)

\(\Rightarrow x=\frac{1}{81}-\frac{5}{3}\)

\(\Rightarrow x=\frac{-134}{81}\)

Vậy \(x=\frac{-134}{81}\)

_Chúc bạn học tốt_

\(x=\dfrac{7}{25}+\dfrac{-1}{5}=\dfrac{7}{25}-\dfrac{1}{5}=\dfrac{2}{25}.\\ x=\dfrac{5}{11}+\dfrac{4}{-9}=\dfrac{5}{11}-\dfrac{4}{9}=\dfrac{1}{99}.\\ \dfrac{5}{9}-\dfrac{x}{-1}=\dfrac{-1}{3}\Leftrightarrow\dfrac{5}{9}+x=-\dfrac{1}{3}.\Leftrightarrow x=-\dfrac{8}{9}.\)

\(x=\dfrac{7}{25}+-\dfrac{1}{5}=>\dfrac{7}{25}+-\dfrac{5}{25}=>x=\dfrac{2}{25}\)

\(x=\dfrac{5}{11}+\dfrac{4}{-9}=>\dfrac{-45}{-99}+\dfrac{44}{-99}=>x=\dfrac{-1}{-99}=\dfrac{1}{99}\)

\(\dfrac{5}{9}-\dfrac{x}{-1}=-\dfrac{1}{3}=>-\dfrac{1}{3}-\dfrac{5}{9}=>\dfrac{x}{-1}=-\dfrac{8}{9}=>x=-\dfrac{8}{9}\)

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