Oxit bazơ : Fe2O3, CuO ;

Axit : H3PO4, HNO3 ;

Bazơ : KOH, Zn(OH)2 ;

Muối : ZnSO4, CuCl2, CuSO4
Tick nha thanks

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Dạng này em tính phân tử khối, nguyên tử khối rồi nhân với 0,16605.10^-23 (g)

Trả lời:

\(a)\)

\(m_C=1,6605.10^{-24}.12=1,9926.10^{-23}\left(g\right)\)

\(m_{Cl}=1,6605.10^{-24}.35,5=5,894775.10^{-23}\left(g\right)\)

\(m_{KOH}=1,6605.10^{-24}.\left(39+16+1\right)=9,2988.10^{-23}\left(g\right)\)

\(m_{H2SO4}=1,6605.10^{-24}.\left(2+32+4.16\right)=1,62729.10^{-22}\left(g\right)\)

\(m_{Fe2\left(CO3\right)3}=1,6605.10^{-24}.\left(2.56+\left(12+3.16\right).3\right)=4,84866.10^{-22}\left(g\right)\)

+) Đơn chất: \(C,Cl.\)

+) Hợp chất: \(KOH,H_2SO_4,Fe_2\left(CO_3\right)_3.\)

\(b)\)

\(m_{BaSO4}=1,6605.10^{-24}.\left(137+32+4.16\right)=3,868965.10^{-22}\left(g\right)\)

\(m_{O2}=1,6605.10^{-24}.\left(2.16\right)=5,3136.10^{-23}\left(g\right)\)

\(m_{Ca\left(OH\right)2}=1,6605.10^{-24}.\left(40+\left(16+1\right).2\right)=1,22877.10^{-22}\left(g\right)\)

\(m_{Fe}=1,6605.10^{-24}.56=9,2988.10^{-23}\left(g\right)\)

+) Đơn chất: \(O_2,Fe.\)

+) Hợp chất: \(BaSO_4,Ca\left(OH\right)_2.\)

\(c)\)

\(m_{HCl}=1,6605.10^{-24}.\left(1+35,5\right)=6,060825.10^{-23}\left(g\right)\)

\(m_{NO}=1,6605.10^{-24}.\left(14+16\right)=4,9815.10^{-23}\left(g\right)\)

\(m_{Br2}=1,6605.10^{-24}.\left(2.80\right)=2,6568.10^{-22}\left(g\right)\)

\(m_K=1,6605.10^{-24}.39=6,47595.10^{-23}\left(g\right)\)

\(m_{NH3}=1,6605.10^{-24}.\left(14+3.1\right)=2,82285.10^{-23}\left(g\right)\)

+) Đơn chất: \(Br_2,K.\)

+) Hợp chất: \(HCl,NO,NH_3.\)

\(d)\)

\(m_{C6H5OH}=1,6605.10^{-24}.\left(12.6+5.1+16+1\right)=1,56087.10^{-22}\left(g\right)\)\(m_{CH4}=1,6605.10^{-24}.\left(12+4.1\right)=2,6568.10^{-23}\left(g\right)\)

\(m_{O3}=1,6605.10^{-24}.\left(3.16\right)=7,9704.10^{-23}\left(g\right)\)

\(m_{BaO}=1,6605.10^{-24}.\left(137+16\right)=2,540565.10^{-22}\left(g\right)\)

+) Đơn chất: \(O_3\)

+) Hợp chất: \(C_6H_5OH,CH_4,BaO.\)

Đơn chất là: Fe;O2;N2;Pb;Au;H2;O3;Cl2;Br2;I2

Hợp chất:CO2;Al 2(SO4)3; CuO;CuCl 2; H2O;Ca(NO3)2;Na2SO3; H3PO4; HCl; NaOH, Mg(OH)2.

Đơn chất là: Fe;O2;N2;Pb;Au;H2;O3;Cl2;Br2;I2

Hợp chất:CO2;Al 2(SO4)3; CuO;CuCl 2; H2O;Ca(NO3)2;Na2SO3; H3PO4; HCl; NaOH, Mg(OH)2.

Muối: CaSO₄, NaHCO₃

Axit: H₂S, HCl

Bazo: NaOH, Ca(OH)₂ , Cu(OH)₂

a) 

đơn chất là: \(C,Cl_2\)

hợp chất là: \(KOH,H_2SO_4,Fe_2\left(CO_3\right)_3\)

\(M_C=12\left(đvC\right)\)

\(M_{Cl_2}=35,5.2=71\left(đvC\right)\)

\(M_{KOH}=1.39+1.16+1.1=56\left(đvC\right)\)

\(M_{H_2SO_4}=1.2+1.32+4.16=98\left(đvC\right)\)

\(M_{Fe_2\left(CO_3\right)_3}=2.56+3.12+9.16=292\left(đvC\right)\)

mấy cái còn lại làm tương tự! giải hết mệt lắm

muối :  
Na3PO4 
NaCl 
Ca(HCO3)2 
KH2PO4 
axit :
HNO3 
HCl 
H2SO4 
H2S 
bazo :
Ca(OH)2 
Fe(OH)3 
NaOH 
KOH 
oxit: 
Fe2O3 
SO2 
K2O 
P2O5 
 

a) Axit : 

- HNO3 : axit nitric

- HCl : axit clohidric

b) Bazo : 

- Fe(OH)3: Sắt (III) hidroxit

c) Muối : 

- AlCl3 : Nhôm clorua

- K2SO4 : kali sunfat

d) Oxit : 

- CuO : Đồng (II) oxit

ui thank nhìu nha