\(\left(a+5\right)\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)

\(\Leftrightarrow ab-6a+5b-30=ab+6a-5b-30\)

\(\Leftrightarrow ab-ab+5b+5b-30+30=6a+6a\)

\(\Leftrightarrow10b=12a\)

\(\Rightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\left(đpcm\right)\)

• \(\frac{a+5}{a-5}\)=\(\frac{b+6}{b-6}\)(ta hoán đổi trung tỉ)=>\(\frac{a+5}{b+6}\)=\(\frac{a-5}{b-6}\)=>\(\frac{\left(a+5\right)-5}{\left(b+6\right)-6}\)=\(\frac{\left(a+5\right)-a}{\left(b+6\right)-b}\)=a/b=5/6

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\left(a+5\right)\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)

\(\Rightarrow ab-6a+5b-30=ab+6a-5b-30\)

\(\Rightarrow5b=6a\)

\(\Rightarrow\frac{a}{b}=\frac{5}{6}\)

Đpcm

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

<=> \(\frac{a-5+10}{a-5}=\frac{b-6+12}{b-6}\)

<=> \(1+\frac{10}{a-5}=1+\frac{12}{b-6}\)

<=> \(\frac{10}{a-5}=\frac{12}{b-6}\)

<=> 10( b - 6 ) = 12( a - 5 )

<=> 5( b - 6 ) = 6( a - 5 )

<=> 5b - 30 = 6a - 30

<=> 5b = 6a

<=> \(\frac{6}{5}=\frac{b}{a}\)hay \(\frac{a}{b}=\frac{5}{6}\)( đpcm )

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

\(\Leftrightarrow\frac{a-5+10}{a-5}=\frac{b-6+12}{b-6}\)

\(\Leftrightarrow1+\frac{10}{a-5}=1+\frac{12}{b-6}\)

\(\Leftrightarrow\frac{10}{a-5}=\frac{12}{b-6}\)

\(\Rightarrow10.\left(b-6\right)=12.\left(a-5\right)\)

\(10b-60=12a-60\)

\(10b=12a\)

\(\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

\(=>\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a+5-\left(a-5\right)}{b+6-\left(b-6\right)}=\frac{a+5-a+5}{b+6-b+6}=\frac{10}{12}=\frac{5}{6}\)

\(\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{a+5+\left(a-5\right)}{b+6+\left(b-5\right)}=\frac{a+5+a-5}{b+6+b-6}=\frac{2a}{2b}=\frac{a}{b}\)

=>\(\frac{a}{b}=\frac{a+5}{b+5}=\frac{5}{6}\)

=>\(\frac{a}{b}=\frac{5}{6}\)

bạn vào câu hỏi tương tự nha

hoặc vào đây: Giúp tôi giải toán - Hỏi đáp, thảo luận về toán học - Học toán với OnlineMath

Ta có: \(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

\(\Rightarrow\left(a+5\right).\left(b-6\right)=\left(a-5\right).\left(b+6\right)\)

\(ab-6a+5b-30=ab+6a-5b-30\)

\(\Rightarrow5b-6a=6a-5b\)

\(5b+5b=6a+6a\)

\(10b=12a\)

\(\Rightarrow\frac{a}{b}=\frac{10}{12}=\frac{5}{6}\)

Vậy \(\frac{a}{b}=\frac{5}{6}\)

Tham khảo nhé~

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow\left(a+5\right).\left(b-6\right)=\left(a-5\right)\left(b+6\right)\)

\(\Rightarrow ab-6a+5b-30=ab+6a-5b-30\)

\(\Rightarrow\left(ab-6a+5b-30\right)-\left(ab+6a-5b-30\right)=0\)

\(\Rightarrow ab-6a+5b-30-ab-6a+5b+30=0\)

\(\Rightarrow-12a+10b=0\)

\(\Rightarrow-12a=10b\Rightarrow\frac{a}{b}=\frac{-10}{12}\Rightarrow\frac{a}{b}=\frac{-5}{6}\)

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\Rightarrow ab+5b-6a-30=ab+6a-5b-30\)

\(\Rightarrow5a-6b=6a-5b\)

\(5a-6a=-5b+6b\)

\(-a=b\)

\(\frac{a}{b}=-1\)

                                                      Bài giải

\(\frac{a+5}{a-5}=\frac{b+6}{b-6}\)

\(\Rightarrow\text{ }\frac{a+5}{b+6}=\frac{a-5}{b-6}=\frac{\left(a+5\right)+\left(a-5\right)}{\left(b+6\right)+\left(b-6\right)}=\frac{2a}{2b}=\frac{a}{b}=\frac{\left(a+5\right)-\left(a-5\right)}{\left(b+6\right)-\left(b-6\right)}=\frac{10}{12}=\frac{5}{6}\)

( Áp dụng tính chất của dãy tỉ số bằng nhau )

\(\Rightarrow\text{ }\frac{a}{b}=\frac{5}{6}\)