Ta có: \(y=f\left(x\right)=2x-3\)

\(f\left(x\right)=0\Rightarrow2x-3=0\Rightarrow x=\dfrac{3}{2}\)

\(f\left(x\right)=1\Rightarrow2x-3=1\Rightarrow x=2\)

\(f\left(x\right)=-\dfrac{3}{2}\Rightarrow2x-3=-\dfrac{3}{2}\Rightarrow x=\dfrac{3}{4}\)

\(f\left(x\right)=2022\Rightarrow2x-3=2022\Rightarrow x=\dfrac{2025}{2}\)

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day nha ban

a: =>x(x+5)=0

=>x=0 hoặc x=-5

a: =>x(x-3)=0

=>x=0 hoặc x=3

giúp mk đi mk cảm ơn

\(f\left(x+2014\right)=5^{x+2014}=5^x.5^{2014}\)

\(f\left(x+2013\right)=5^{x+2013}=5^x.5^{2013}\)

\(\Rightarrow f\left(x+2014\right)-f\left(x+2013\right)=5^x.5^{2014}-5^x.5^{2013}\)

\(=5^x.5^{2013}.\left(5-1\right)=5^x.5^{2013}.4=4\)

\(\Rightarrow5^{x+2013}=1\)

\(\Rightarrow x+2013=0\)

\(x=-2013\)

Ta có \(y=f\left(x\right)=5^x\)

\(\Rightarrow f\left(x+2014\right)=5^{x+2014}\) và \(f\left(x+2013\right)=5^{x+2013}\)

\(\Rightarrow f\left(x+2014\right)-f\left(x+2013\right)=4\Leftrightarrow5^{x+2014}-5^{x+2013}=4\)

\(\Leftrightarrow5^x.5^{2014}-5^x.5^{2013}=4\)

\(\Leftrightarrow5^x.5^{2013}.\left(5^1-1\right)=4\)

\(\Leftrightarrow5^{x+2013}.4=4\)

\(\Rightarrow5^{x+2013}=1\Rightarrow x+2013=0\Leftrightarrow x=-2013\)

Vậy x=-2013