ta có : \(4x^2+4y^2-2xy-6x-6y+6\)

\(=x^2-2xy+y^2+3x^2-6x+3+3y^2-6y+3\)

\(=\left(x-y\right)^2+3\left(x-1\right)^2+3\left(y-1\right)^2\ge0\forall x;y\left(đpcm\right)\)

Chứng minh gì á bạn?

CM như kiểu là bé hoặc lớn hơn 0 vs mọi x,y á bạn thầy cô mk ghi đề vậy thì mk viết vậy thôi ạ

a: Ta có: \(x^2-8x+20\)

\(=x^2-8x+16+4\)

\(=\left(x-4\right)^2+4>0\forall x\)

b: Ta có: \(-x^2+6x-19\)

\(=-\left(x^2-6x+19\right)\)

\(=-\left(x^2-6x+9+10\right)\)

\(=-\left(x-3\right)^2-10< 0\forall x\)

a) \(3x^2-3xy-5x+5y\)

\(=\left(3x^2-3xy\right)-\left(5x-5y\right)\)

\(=3x\left(x-y\right)-5\left(x-y\right)\)

\(=\left(x-y\right)\left(3x-5\right)\)

b) \(2x^3y-2xy^3-4xy^2-2xy\)

\(=2xy\left(x^2-y^2-2y-1\right)\)

\(=2xy\left[x^2-\left(y^2+2y+1\right)\right]\)

\(=2xy\left[x^2-\left(y+1\right)^2\right]\)

\(=2xy\left(x-y-1\right)\left(x+y+1\right)\)

c) \(x^2+1+2x-y^2\)

\(=\left(x^2+2x+1\right)-y^2\)

\(=\left(x+1\right)^2-y^2\)

\(=\left(x+1+y\right)\left(x+1-y\right)\)

d) \(x^2+4x-2xy-4y+y^2\)

\(=\left(x^2-2xy+y^2\right)+\left(4x-4y\right)\)

\(=\left(x-y\right)^2+4\left(x-y\right)\)

\(=\left(x-y\right)\left(x-y+4\right)\)

e) \(x^3-2x^2+x\)

\(=x\left(x^2-2x+1\right)\)

\(=x\left(x-1\right)^2\)

f) \(2x^2+4x+2-2y^2\)

\(=2\left(x^2+2x+1-y^2\right)\)

\(=2\left[\left(x^2+2x+1\right)+y^2\right]\)

\(=2\left[\left(x+1\right)^2-y^2\right]\)

\(=2\left(x-y+1\right)\left(x+y+1\right)\)

a: =3x(x-y)-5(x-y)

=(x-y)(3x-5)

b: \(=2xy\left(x^2-y^2-2y-1\right)\)

\(=2xy\left[x^2-\left(y^2+2y+1\right)\right]\)

\(=2xy\left(x-y-1\right)\left(x+y+1\right)\)

d:

Sửa đề: x^2+4x-2xy-4y+y^2

=x^2-2xy+y^2+4x-4y

=(x-y)^2+4(x-y)

=(x-y)(x-y+4)

e: =x(x^2-2x+1)

=x(x-1)^2

f: =2(x^2+2x+1-y^2)

=2[(x+1)^2-y^2]

=2(x+1+y)(x+1-y)

\(a,VT=\left(a+b+c\right)\left(a-b+c\right)\)

\(=\left(a+c+b\right)\left(a+c-b\right)\)

\(=\left(a+c\right)^2-b^2\)

\(=a^2+2ac+c^2-b^2=VP\)

\(b,VT=\left(3x+2y\right)\left(3x-2y\right)-\left(4x-2y\right)\left(4x+2y\right)\)

\(=9x^2-4y^2-16x^2+4y^2=-7x^2=VP\)

\(c,VT=x^3-1-x^3-1=-2=VP\)

\(d,VT=8x^3+1-8x^3+1=2=VP\)

\(e,VT=\left(x^2+2xy+4y^2\right)\left(x-2y-2x+1\right)\)

\(=\left(x^2+2xy+4y^2\right)\left(-x-2y+1\right)\)

\(=-x^3-2x^2y+x^2-2x^2y-4xy^2+2xy-4xy^2-8y^3+4y^2\)

( bn kiểm tra lại đề nhé)

\(2x^2+2y^2+2xy-4x+4y+8=0\)

\(\Leftrightarrow\left(x^2+2xy+y^2\right)+\left(x^2-4x+4\right)+\left(y^2+4y+4\right)=0\)

\(\Leftrightarrow\left(x+y\right)^2+\left(x-2\right)^2+\left(y+2\right)^2=0\)

\(\rightarrow x=-y=2\)