Tham khảo

\(A=\left(b+a\right)+\left(c-d\right)-\left(c+a\right)-\left(b-d\right)\)

\(A=b+a+c-d-c-a-b+d\)

\(A=\left(b-b\right)+\left(a-a\right)+\left(c-c\right)+\left(-d+d\right)\)

\(A=0\)

\(B=\left(a-d\right)-\left(d+a\right)-\left(c-d\right)+\left(c+b\right)\)

\(B=a-d-d-a-c+d+c+b\)

\(B=\left(a-a\right)+\left(d-d+d\right)+\left(-c+c\right)+b\)

\(B=d+b\)

a) Ta có: \(A=\left(b+a\right)+\left(c-d\right)-\left(c+a\right)-\left(b-d\right)\)

\(=a+b+c-d-c-a-b+d\)

=0

b) Ta có: \(B=\left(a-d\right)-\left(a+d\right)-\left(c-d\right)+\left(c+b\right)\)

\(=a-d-a-d-c+d+c+b\)

=b-d

a, = a+b-c-b+c-d

=a+(b-b)-(c-c)-d

=a+0-0-d

=a-d

các câu khác tương tự

a)(a + b - c) - (b - c + d)

=a + b - c - b + c - d

=a + (b - b) -(c + c) - d

=a + 0 - c² - d

b)- (a - b + c) + (a - b + d)

=-a + b - c + a - b + d

=(-a + a) + (b - b) - c + d

=0 + 0 - c + d

c) -(a + b) - (-a - b + c)

=-a - b + a + b - c

=(-a + a) - (b + b) - c

=0 - b² - c

d)(a - b) - (c - d) - (a - c)

=a - b - c + d - a + c

=(a - a) - b - (c + c) + d

=0 - b - c² + dd

Mỏi cả tay😧

Bỏ ngoặc ra rồi tính bình thường

bỏ ngoặc nha bn

nhấn vào đúng 0 sẽ ra

a,-b-(b-a+c)

=-b-b+a-c

=2*(-b)+a-c

b,-(a-b+c)-(c-a)

=-a+b-c-c+a

=(-a+a)+b-2*(-c)

=b-2*(-c)

c,b-(b+a-c)

=b-b-a+c

=0-a+c

d,a-(-b+a-c)

=a+b-a+c

=(a-a)+b+c

=b+c

c,f  fk,l,xskooe

1) Đơn giản biểu thức SAU khi bỏ dấu ngoặc:

a) - a - (b - a - c) = -a - b + a + c = -b + c

b) - (a - c) - (a - b - c) = - a + c - a + b + c = - 2a + 2c + b

c) b - (b + a - c) = b - b - a + c = - a + c

d) - (a - b - c) - (a + b + c) = -a + b + c - a - b - c = -2a 

a) \(-a-\left(b-a-c\right)=-a+b+a+c=b+c\)

b) \(-\left(a-c\right)-\left(a-b-c\right)=-a+c-a+b+c=-2a+2c+b\)

c) \(b-\left(b+a-c\right)=b-b-a+c=-a+c\)

d) \(-\left(a-b-c\right)-\left(a+b+c\right)=-a+b+c-a-b-c=-2a\)