1,5376-0,5952+0,0576

=1

tk nha bn

\(1,24^2-2,48.0,24+0,24=\frac{739}{625}\)

\(1,24x^2-2,48.0,24+0,24\)

\(\Leftrightarrow1,24x^2-2.2,48.0,24+0,24^2\)

\(\Leftrightarrow1,24x^2-1,2+0,1\)

97² - 3² = (97 +3)(97 - 3)=100.94=9400

giúp mình nhé ^^

\(205^2-95^2=\)

\(=\left(205-95\right)\left(205+95\right)\)

\(=200.300\)

\(=60000\)

\(36^2-14^2=\)

\(=\left(36-14\right)\left(36+14\right)\)

\(=22.50\)

\(=1100\)

\(205^2-95^2=\left(205-95\right)\left(205+95\right)=110.300=33000\)

\(36^2-14^2=\left(36-14\right)\left(36+14\right)=22.50=1100\)

\(97^2-3^2=\left(97-3\right)\left(97+3\right)=94.100=9400\)

\(1,24^2-2,48\times0,24+0,24^2\)

\(=1,24-2\times1,24\times0,24+0,24^2\)

\(=\left(1,24-0,24\right)^2\)

\(=1\)

A= x³- 9x²+ 27x- 27 tại x=13, ta có: 

A= 13³- 9.13²+ 27.13- 27

A= 13³- 3.3.13²+ 3.3³.13- 3³

A= (13- 3)³

A= 10³

^{A= 1000}

^{Vậy đa thức A tại x= 13 có kết quả bằng 1000}

`A  = x^3 - 9x^2 +27x - 27`

`->A = x^3 - 3 . x^2 . 3 + 3 . x . 3^2 -3^3`

`->A = (x-3)^3`

`->A = (13-3)^3`

`->A=10^3=10 000`

Vậy `A=10 000`

25² - 15²

= (25 - 15)(25 + 15)

= 10 . 40

= 400

205² - 95²

= (205 - 95)(205 + 95)

= 110 . 300

= 33 000

36² - 14²

= (36 - 14)(36 + 14)

= 22 . 50

= 1 100

950² - 850²

= (950 - 850)(950 + 850)

= 100 . 1 800

= 180 000

cảm ơn nhé

a)\(25^2-15^2=\left(25-15\right)\left(25+15\right)=10.40=400\)

b)\(205^2-95^2=\left(205-95\right)\left(205+95\right)=110.300=33000\)

c)\(36^2-14^2=\left(36-14\right)\left(36+14\right)=22.50=1100\)

d)\(950^2-850^2=\left(950-850\right)\left(950+850\right)=100.1800=180000\)

Xong rồi đấy,chúc bạn học tốt