a-b=5

<=>(a-b)²=a²-2ab+b² =25

<=>a²+b²-2ab =33

<=>a²+b² = 33 (vì 2ab=8)

Ta có:

a³-b³= (a-b)(a²+ab+b²)

=5.(33+4) =185

Ta có: \(a+b=8\)

\(\Rightarrow\left(a+b\right)^2=8^2\)

\(\Rightarrow a^2+2ab+b^2=64\)

\(\Rightarrow a^2+2.10+b^2=64\)

\(\Rightarrow a^2+20+b^2=64\)

\(\Rightarrow a^2+b^2=44\)

\(\left(a-b\right)^2=a^2-2ab+b^2\)

\(=\left(a^2+b^2\right)-2.10\)

\(=44-20\)

\(=24\)

Vậy \(\left(a-b\right)^2=24\)

(a-b)² = a²-2ab+b²

= a²+2ab+b² -4ab

⁼(a+b)²- 4ab

=8² - 4.10

=64-40

=24

thanks

Evaluate the expression at

x³ + 12x + 48x + 64

= (x + 4)²

= (- 4 + 4)²

= 0²

= 0

Fill in the blank: ............

x³ - a = (x - 2)(x² + 2x + 4)

x³ - a = x³ - 8

a = 8

a + b = 8

(a + b)² = 8²

a² + b² + 2ab = 64

a² + b² + 2 . 10 = 64

a² + b² + 20 = 64

a² + b² = 64 - 20

a² + b² = 44

(a - b)²

= a² - 2ab + b²

= 44 - 2 . 10

= 44 - 20

= 24
Given .
Evaluate A at .
Answer: A

A = (x - 5)(x² + 5x + 25) - x²(x + 3) + 3x²

= x³ - 125 - x³ - 3x² + 3x²

= - 125

Given .
Evaluate A at .
Answer: A

5

bạn giải chi tiết giúp mình được ko

minh cung chiu

chỗ tiếng việt chỗ tiếng anh là sao

mk nghĩ là -1

Cảm ơn bn

\(\frac{x^3+x^2-4x-4}{x^3+8x^2+17x+10}=\frac{x^2\left(x+1\right)-4\left(x+1\right)}{x^2\left(x+1\right)+7x\left(x+1\right)+10\left(x+1\right)}\)

\(=\frac{\left(x+1\right)\left(x^2-4\right)}{\left(x+1\right)\left(x^2+7x+10\right)}=\frac{\left(x+2\right)\left(x-2\right)}{x\left(x+2\right)+5\left(x+2\right)}\)

\(=\frac{\left(x+2\right)\left(x-2\right)}{\left(x+2\right)\left(x+5\right)}=\frac{x-2}{x+5}\Rightarrow a=-2;b=5\)

\(\Rightarrow\)\(a+b=-2+5=3\)