\(\frac{12,48:0,5x6,25x4x2}{2x3,12x1,25:0,25x10}=\frac{4x3,12x2x5x1,25x4x2}{2x3,12x1,25x4x2x5}=4\)

hôm nay tôi vừa làm xong

Lời giải:
Gọi phân số trên là $A$. Ta có:

$A=\frac{12,48:6,48\times 2\times 8\times 6,25\times 3,25\times 4\times 4\times 2}{3,12\times 21,6\times 1,25\times 2,6\times 4\times 4\times 10\times 10}$

$=\frac{12,48:6,48\times (2\times 6,25)\times (8\times 3,25)\times 2}{3,12\times 21,6\times (1,25\times 10)\times (2,6\times 10)}$

$=\frac{12,48:6,48\times 12,5\times 26\times 2}{3,12\times 21,6\times 12,5\times 26}$

$=\frac{12,48:6,48\times 2}{3,12\times 21,6}=\frac{125}{2187}$

chịu thôi

.

.

.

hỏi chị tuyển đi

Mk có trả lời câu này trên h rồi, bạn cứ vào link này để xem nhé! Nếu bạn thấy sai chỗ nào thì mong bạn giúp đỡ...
Link: https://h.vn/hoi-dap/question/633709.html

= \(\frac{1x1x1}{1x2x4}x\frac{2.2.1}{1.1.2.2}=\frac{1}{8}.1=\frac{1}{8}\)

=1X2X3/1X2X3X4X2= 1/8                 =3X2X2X2X5/3X2X2X5X2= 1/1

=1/8X1/1=1/8

\(\frac{2}{1\times2}+\frac{2}{2\times3}+\frac{2}{3\times4}+...+\frac{2}{9\times10}\)

=\(2\times\frac{1}{1\times2}+2\times\frac{1}{2\times3}+2\times\frac{1}{3\times4}+...+2\times\frac{1}{9\times10}\)

=\(2\times\left(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{9\times10}\right)\)

=\(2\times\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)

=\(2\times\left(\frac{1}{1}-\frac{1}{10}\right)=2\times\left(\frac{10}{10}-\frac{1}{10}\right)=2\times\frac{9}{10}\)

=\(\frac{9}{5}\)

=2-1+1-\(\frac{2}{3}\)+\(\frac{2}{3}\)-\(\frac{1}{2}\)+...+\(\frac{2}{9}\)-\(\frac{1}{5}\)

=2-\(\frac{1}{5}\)

=\(\frac{10}{5}\)-\(\frac{1}{5}\)

=\(\frac{9}{5}\).

**** mình nha mấy bạn.

\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}\right)+\frac{1}{2}.\left(\frac{1}{2.3}-\frac{1}{3.4}\right)+...+\frac{1}{2}.\left(\frac{1}{8.9}-\frac{1}{9.10}\right)\)

\(=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)\)

\(\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{9.10}\right)=\frac{1}{2}.\frac{22}{45}=\frac{11}{45}\)